True or False: In order to solve an equation, we must isolate the variable.

Mathematics

2 answers:

TEA [102]2 years ago

4 0

The answer is false. in order to solve an equation you must reverse the operations acting on the variable

vaieri [72.5K]2 years ago

3 0

Answer:

It is False

But it's not true

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Please answer this question only if you know the answer!! 26 points and brainliest!

oksano4ka [1.4K]

Answer:

(4,3) is the answer

Step-by-step explanation:

4 0

3 years ago

Write a division problem whose quotient has its first digit in the hundreds place

Margaret [11]

Quotient is another name for the answer to a division problem

the hundreds place is the 3rd number before the decimal, 9999999.0
^this one

so you need to find a division problem that equals something between 100 and 999

1000 divided by 10 is a good one, the answer to that problem is 100, and 100 has its first digit in the hundreds place.

8 0

3 years ago

Find derivative problem Find B’(6)

dalvyx [7]

Answer:

$B^\prime(6) \approx -28.17$

Step-by-step explanation:

We have:

$\displaystyle B(t)=24.6\sin(\frac{\pi t}{10})(8-t)$

And we want to find B’(6).

So, we will need to find B(t) first. To do so, we will take the derivative of both sides with respect to x. Hence:

$\displaystyle B^\prime(t)=\frac{d}{dt}[24.6\sin(\frac{\pi t}{10})(8-t)]$

We can move the constant outside:

$\displaystyle B^\prime(t)=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)]$

Now, we will utilize the product rule. The product rule is:

$(uv)^\prime=u^\prime v+u v^\prime$

We will let:

$\displaystyle u=\sin(\frac{\pi t}{10})\text{ and } \\ \\ v=8-t$

Then:

$\displaystyle u^\prime=\frac{\pi}{10}\cos(\frac{\pi t}{10})\text{ and } \\ \\ v^\prime= -1$

(The derivative of u was determined using the chain rule.)

Then it follows that:

$\displaystyle \begin{aligned} B^\prime(t)&=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)] \\ \\ &=24.6[(\frac{\pi}{10}\cos(\frac{\pi t}{10}))(8-t) - \sin(\frac{\pi t}{10})] \end{aligned}$