Answer:
-1/6
Step-by-step explanation:
(10 - 8)/(-21 + 9)= 12/-12= -1
y - 8 = -1(x + 9)
y - 8 = -x - 9
y = -x - 1
Given:
The given quadratic polynomial is :

To find:
The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.
Solution:
We have,

Equate the polynomial with 0 to find the zeroes.

Splitting the middle term, we get




The zeroes of the given polynomial are -3 and 4.
The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.
A quadratic polynomial is defined as:




Therefore, the required polynomial is
.
The answer is 5x + 10 because you have to times 5 by everything in the parenteses
Well from positive y axis Q is situated at 6 units while P is situated at 3 units.
So length of PQ - 6+3 = 9 units.
Rounding up your answer is 10 units