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3 years ago

What is the simplified form of 2(15-3)x(15-3)divided by 2?

Mathematics

1 answer:

Darya [45]3 years ago

7 0

PEMDAS
2(12)x(12)/2
24x12/2
288/2
144

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Which function has the graph shown?

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Answer:

D) -cos(x)

Step-by-step explanation:

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2 years ago

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What question 4 or 5?oh....

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2 years ago

The average of five distinct scores has the same value as the median of the five scores. The sum of the five scores is 420. What

givi [52]

Answer:

The sum of five scores that is not the median is, 336

Step-by-step explanation:

Average defined as the the sum of the observation to the total number of the observation.

Given: The sum of the five scores is 420

Then, by definition of average;

Average of five distinct score = $\frac{420}{5} = 84$

It is also, given that the average of five distinct scores has the same value as the median of the five scores.

⇒Median of five scores = 84

Since, scores are distinct, therefore

Sum of all scores that is not the median = Sum of five scores - median = 420-84 = 336

therefore, the sum of five scores that is not the median is, 336

3 0

2 years ago

One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second

algol13

Answer:

Therefore the third container contains $\frac{735}{17}\%$ = 43.23 % acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

$= (V\times \frac{100+55}{100})$ cubic unit.

$=\frac{155}{100}V$ cubic unit.

The amount of acid in first container is

$=V\times \frac{25}{100}$ cubic unit.

$=\frac{25}{100}V$ cubic unit.

The amount of acid in second container is

$=(\frac{155}{100}V \times \frac{55}{100})$ cubic unit.

$=\frac{8525}{10000}V$ cubic unit.

Total amount of acid $=(\frac{25}{100}V+\frac{8525}{10000}V)$ cubic unit.

$=(\frac{2500+8525}{10000}V)$ cubic unit.

$=(\frac{11025}{10000}V)$ cubic unit.

Total volume of mixture $=(V+\frac{155}{100}V)$ cubic unit.

$=\frac{100+155}{100}V$ cubic unit.

$=\frac{255}{100}V$ cubic unit.

The amount of acid in the mixture is

$=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%$

$=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%$

$=\frac{735}{17}\%$

Therefore the third container contains $\frac{735}{17}\%$ acid.

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2 years ago

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Gwar [14]

Answer:

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Step-by-step explanation:

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2 years ago