Hello from MrBillDoesMath!
Answer:
45 (all three: 45, 45, 90)
Discussion:
Let "x" be the base angle in the isosceles triangle. As base angles are equal in an isosceles triangle and a triangle contains 180 degrees:
x + x + 90 = 180 =>
2x + 90 = 180 => subtract 90 from both sides
2x = 180 -90 =>
2x = 90 => divide both sides by 2
x = 45
Thank you,
MrB
Rate = 85 minutes/10 miles
he runs a mile every 8.5 minutes
8 x 8.5 =68
This is because you multiply the Mileage(8) by the rate that was aquired. :)
Answer: 819.73 yd²
<u>Step-by-step explanation:</u>

= 
= 
= 29 * 30
= 870

= π(4)²
= 16π
≈ 50.27
Area of the park = 
= 870 - 50.27
= 819.73
Answer: -7 = q
Step-by-step explanation:
There are

ways of selecting two of the six blocks at random. The probability that one of them contains an error is

So

has probability mass function

These are the only two cases since there is only one error known to exist in the code; any two blocks of code chosen at random must either contain the error or not.
The expected value of finding an error is then