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2 years ago

14

5/9 x 3 3/5 simplest form Show work please!

2 answers:

Alex777 [14]2 years ago

8 0

Answer:

2

Step-by-step explanation:

I wrote 3 3/5 as an improper fraction

5/9*18/5

Then I solved and simplified

I got <u>2</u>

blsea [12.9K]2 years ago

3 0

Answer:

2

Step-by-step explanation:

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Abel Alonzo, Director of Human Resources, is exploring employee absenteeism at the Plano Power Plant. Ten percent of all plant e

Alex17521 [72]

Answer: 0.23

Step-by-step explanation:

Given : F is the event "works in the finishing department;"

and A is the event "is absent excessively."

Given : 10% of all plant employees work in the finishing department; 20% of all plant employees are absent excessively; and 7% of all plant employees work in the finishing department and are absent excessively.

i.e. P(A)= 0.20 ; P(F)=0.10 ; P(A ∩ F) = 0.07

We know that $P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)$

Then,

$P(A\cup F)=P(A)+P(F)-P(A\cap F)\\\\\Rightarrow\ P(A\cup F)=0.20+0.10-0.07=0.23$

Hence, the required answer is $P(A\cup F)=0.23$

5 0

2 years ago

Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro

Ugo [173]

Answer:

$Side\ B = 6.0$

$\alpha = 56.3$

$\theta = 93.7$

Step-by-step explanation:

Given

Let the three sides be represented with A, B, C

Let the angles be represented with $\alpha, \beta, \theta$

[See Attachment for Triangle]

$A = 10cm$

$C = 12cm$

$\beta = 30$

What the question is to calculate the third length (Side B) and the other 2 angles ( $\alpha\ and\ \theta$ )

Solving for Side B;

When two angles of a triangle are known, the third side is calculated as thus;

$B^2 = A^2 + C^2 - 2ABCos\beta$

Substitute: $A = 10$ , $C =12$ ; $\beta = 30$

$B^2 = 10^2 + 12^2 - 2 * 10 * 12 *Cos30$

$B^2 = 100 + 144 - 240*0.86602540378$

$B^2 = 100 + 144 - 207.846096907$

$B^2 = 36.153903093$

Take Square root of both sides

$\sqrt{B^2} = \sqrt{36.153903093}$

$B = \sqrt{36.153903093}$

$B = 6.0128115797$

$B = 6.0$ <em>(Approximated)</em>

Calculating Angle $\alpha$

$A^2 = B^2 + C^2 - 2BCCos\alpha$

Substitute: $A = 10$ , $C =12$ ; $B = 6$

$10^2 = 6^2 + 12^2 - 2 * 6 * 12 *Cos\alpha$

$100 = 36 + 144 - 144 *Cos\alpha$

$100 = 36 + 144 - 144 *Cos\alpha$

$100 = 180 - 144 *Cos\alpha$

Subtract 180 from both sides

$100 - 180 = 180 - 180 - 144 *Cos\alpha$

$-80 = - 144 *Cos\alpha$

Divide both sides by -144

$\frac{-80}{-144} = \frac{- 144 *Cos\alpha}{-144}$

$\frac{-80}{-144} = Cos\alpha$

$0.5555556 = Cos\alpha$

Take arccos of both sides

$Cos^{-1}(0.5555556) = Cos^{-1}(Cos\alpha)$

$Cos^{-1}(0.5555556) = \alpha$

$56.25098078 = \alpha$

$\alpha = 56.3$ <em>(Approximated)</em>

Calculating $\theta$

Sum of angles in a triangle = 180

Hence;

$\alpha + \beta + \theta = 180$

$30 + 56.3 + \theta = 180$

$86.3 + \theta = 180$

Make $\theta$ the subject of formula

$\theta = 180 - 86.3$

$\theta = 93.7$

5 0

2 years ago

If sx = 35, then x = 7

Ostrovityanka [42]

Answer:

s=5

Step-by-step explanation:

35 divided by 7 equals 5

8 0

2 years ago

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What is bigger 9/10 or .71

yuradex [85]

9/10 because that equals .9

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3 years ago

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Which expression represents the product of b and 34?

Debora [2.8K]

The correct choice is B

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2 years ago

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