Answer:
the answer is 14 C
Step-by-step explanation:
just took the test?
Answer: A is the correct answer
Step-by-step explanation: D has a removable discontinuity at x =-3 and is not continuous.
Answer:
The product of (-5·q·r) × (-2·p·q·r) × p·q is 10·q³·r²·p²
Step-by-step explanation:
The question relates to the rules of multiplication of variables and indices rules, and simplifification of an expression ;
The given expression is (-5·q·r) × (-2·p·q·r) × p·q
Therefore, we have;
(-5·q·r) × (-2·p·q·r) × p·q = (-5) × (-2) × q×q×q × r×r ×p×p = 10 × q³ × r² × p²
10 × q³ × r² × p² = 10·q³·r²·p²
∴ (-5·q·r) × (-2·p·q·r) × p·q = 10 × q³ × r² × p² = 10·q³·r²·p²
(-5·q·r) × (-2·p·q·r) × p·q = 10·q³·r²·p².
=x^2-8x+16-16
= (x-4) ^2-16
=[(x-4) -4][(x-4) +4]
=(x-8) x
<u>Answer-</u>
<em>D. The function has one real zero and two nonreal zeros. The graph of the function intersects the x-axis at exactly one location.</em>
<u>Solution-</u>
The given polynomial is,
The zeros of the polynomials are,
Therefore, this function has only one real zero i.e 1 and two nonreal zeros i.e ±√6i . The graph of the function intersects the x-axis at exactly one location i.e at x = 1
