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Dmitrij [34]
3 years ago
5

What two-digit numbers greater than 69 are divisible by 2 and 11?

Mathematics
1 answer:
Mariulka [41]3 years ago
8 0
88... 88/11=8 and 88/2=44
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I don't get this can somone help me please ​
wolverine [178]

Answer:

f = m+h

Step-by-step explanation:

just add h to both sides of the equation to isolate f.

Hope this helps!

7 0
3 years ago
Choose 5 cards from a full deck of 52 cards with 13values (2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K, A) and 4 kinds(spade, diamond, h
Delvig [45]

Answer:

a) 182 possible ways.

b) 5148 possible ways.

c) 1378 possible ways.

d) 2899 possible ways.

Step-by-step explanation:

The order in which the cards are chosen is not important, which means that we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question, we have that:

There are 52 total cards, of which:

13 are spades.

13 are diamonds.

13 are hearts.

13 are clubs.

(a)Two-pairs: Two pairs plus another card of a different value, for example:

2 pairs of 2 from sets os 13.

1 other card, from a set of 26(whichever two cards were not chosen above). So

T = 2C_{13,2} + C_{26,1} = 2*\frac{13!}{2!11!} + \frac{26!}{1!25!} = 182

So 182 possible ways.

(b)Flush: five cards of the same suit but different values, for example:

4 combinations of 5 from a set of 13(can be all spades, all diamonds, and hearts or all clubs). So

T = 4*C_{13,5} = 4*\frac{13!}{5!8!} = 5148

So 5148 possible ways.

(c)Full house: A three of a kind and a pair, for example:

4 combinations of 3 from a set of 13(three of a kind ,c an be all possible kinds).

3 combinations of 2 from a set of 13(the pair, cant be the kind chosen for the trio, so 3 combinations). So

T = 4*C_{13,3} + 3*C_{13.2} = 4*\frac{13!}{3!10!} + 3*\frac{13!}{2!11!} = 1378

So 1378 possible ways.

(d)Four of a kind: Four cards of the same value, for example:

4 combinations of 4 from a set of 13(four of a kind, can be all spades, all diamonds, and hearts or all clubs).

1 from the remaining 39(do not involve the kind chosen above). So

T = 4*C_{13,4} + C_{39,1} = 4*\frac{13!}{4!9!} + \frac{39!}{1!38!} = 2899

So 2899 possible ways.

4 0
3 years ago
Based on the information marked in the diagram, AABC and ADEF must be
Studentka2010 [4]

Answer:

a

Step-by-step explanation:

answer

8 0
3 years ago
What is the are and perimeter of these 4 problems
Allisa [31]

Answer:

1.A:32 P:24

2.A:40 P:26

Step-by-step e1.xplanation:

2. its the same as a rectangle if you cut it you can turn it into a rectangle

7 0
4 years ago
effie ate 4 peaches. this represents 50% of the bag of peaches. how many peaches were originally in the bag?
Marat540 [252]

8 peaches. 8 peaches because if effie ate 4 peaches, or half of the bag, you would have to multiply 4 by 2 to get the answer of 8 peaches. mark brainliest please!

4 0
3 years ago
Read 2 more answers
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