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g100num [7]
2 years ago
14

True or false 2 quarts is > 10 pints

Mathematics
1 answer:
Firdavs [7]2 years ago
3 0
1quart=2pints
convert 2 points to quarts
2 quarts=2 times 2 pints=4 pints

now we have
4pints>10pints
false since 4>10

FALSE

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Debora [2.8K]
<h3>Answer:  Yes</h3>

========================================================

Explanation

The ratio 8:10 simplifies to 4:5 when you divide both parts by 2.

The ratio 16:20 simplifies to 4:5 when you divide both parts by 4

Therefore the two ratios 8:10 and 16:20 are both equal 4:5, so they are equal to one another.

------------

Put another way,

(8 large)/(10 small) = (16 large)/(20 small)

8/10 = 16/20

8*20 = 10*16 ... cross multiply

160 = 160

We get a true equation, so the first equation is true as well.

This shows the ratios are equivalent.

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Or you could have...

(8 large)/(16 large) = (10 small)/(20 small)

8/16 = 10/20

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We get the same conclusion as before.

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2 years ago
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Step-by-step explanation:

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Debora [2.8K]

Answer:

statistic value t= 5.43

p-value: < 0.00001.

Step-by-step explanation:

Hello!

To obtain information over the corrosion-resistance properties of a certain type of steel conduit a random sample of 45 specimens was taken and buried for two years.

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The hypothesis is:

H₀: μ ≤ 50

H₁: μ > 50

α: 0.05

To choose the corresponding statistic to use to study the population mean, the variable must have a normal distribution. There is no available information to check this, so I'll just assume that the variable has a normal distribution and, since the population variance is unknown and the sample is small, the statistic to use is a Student t.

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Critical value:

t_{n-1; 1-\alpha } = t_{44; 0.95} = 1.68

Rejection rule:

Reject the null hypothesis when t ≥ 1.68

t= \frac{53.4 - 50}{\frac{4.2}{\sqrt{45} } }

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The calculated value is greater than the critical value, thedecision is to rject the null hypothesis.

p-value:

P(t ≥ 5.43) = 1 - P(t < 5.43) = < 0.00001.

The p-value is less than α so the decision is to reject the null hypothesis.

Since the null hypothesis was rejected, then the population average of the penetration of the conduits specimens is greater than 50 mils. It is not recommendable to use these conduits.

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