Solve for s.<br> 48 = -85<br> Answer:

A flat circular plate has the shape of the region x squared plus y squared less than or equals 1.The plate, including the bound

rjkz [21]

Answer:

We have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . and the hottest value is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

Step-by-step explanation:

We need to take the derivative with respect of x and y, and equal to zero to find the local minimums.

The temperature equation is:

$T(x,y)=x^{2}+2y^{2}-\frac{3}{2}x$

Let's take the partials derivatives.

$T_{x}(x,y)=2x-\frac{3}{2}=0$

$T_{y}(x,y)=4y=0$

So, we can find the critical point (x,y) of T(x,y).

$2x-\frac{3}{2}=0$

$x=\frac{3}{4}$

$4y=0$

$y=0$

The critical point is (3/4,0) so the temperature at this point is: $T(\frac{3}{4},0)=(\frac{3}{4})^{2}+2(0)^{2}-(\frac{3}{2})(\frac{3}{4})$

$T(\frac{3}{4},0)=-\frac{9}{16}$

Now, we need to evaluate the boundary condition.

$x^{2}+y^{2}=1$

We can solve this equation for y and evaluate this value in the temperature.

$y=\pm \sqrt{1-x^{2}}$

$T(x,\sqrt{1-x^{2}})=x^{2}+2(1-x^{2})-\frac{3}{2}x$

$T(x,\sqrt{1-x^{2}})=-x^{2}-\frac{3}{2}x+2$

Now, let's find the critical point again, as we did above.

$T_{x}(x,\sqrt{1-x^{2}})=-2x-\frac{3}{2}=0$

$x=-\frac{3}{4}$

Evaluating T(x,y) at this point, we have:

$T(-(3/4),\sqrt{1-(-3/4)^{2}})=-(-\frac{3}{4})^{2}-\frac{3}{2}(-\frac{3}{4})+2$

$T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$

Now, we can see that at point (3/4,0) we have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . On the other hand, at the point $-(3/4),\frac{\sqrt{7}}{4})$ we have the hottest value of temperature, it is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

I hope it helps you!

4 0

2 years ago

A box of cereal has a volume of 144 inches squared. the height of the cereal box is 12 inches, and the depth is 2 inches. what i

Nutka1998 [239]

The value of the given cone with a volume of 144 has a width is 6 inches.

We have given that,

A box of cereal has a volume of 144 inches squared.

The height of the cereal box is 12 inches, and the depth is 2 inches.

The volume of cone = 144 inches squared.

height=12 inches

depth=2inches

<h3>What is the formula of the cube?</h3>

Area of a cube = V = L * W * H

L-length

W-width

H-height

We have to determine the width cereal box.

Plug the given values in the formula

V = L * W * H

144=2×12×width

Width=144/24

Width=6inches

Therefore the value of the width is 6 inches.

To learn more about the volume visit:

brainly.com/question/1972490

#SPJ1

5 0

1 year ago

F(x) = x 2+ 6 and g(x) = 2x - 1<br><br> g[f(x)] =

Tasya [4]

Answer:

Given,

f(x)=x^2+6

g(x)=2x-1

Now,

g[f(x)]=g(x^2+6) since f(x)=x^2+6

=2(x^2+6)-1 since x > x^2+6

=2x^2+12-1

=2x^2+11

6 0

3 years ago

A table that originally cost $196 is on sale for $160.00 what is the percent of decrease rounded to the nearest tenth ?

kifflom [539]

It’s 20% rounded to the nearest tenth

5 0

3 years ago

Read 2 more answers

Idk this plz help me

Alik [6]

Answer:

1. {12,0}

hope it helps.

5 0

2 years ago

Read 2 more answers

Solve for s. 48 = -85 Answer: