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mamaluj [8]
3 years ago
10

Solve for s. 48 = -85 Answer:

Mathematics
1 answer:
ira [324]3 years ago
3 0

Answer:

Step-by-step explanatio

s = 12

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Assume that y varies directly with x. If y=9 when x=−3, find x when y=6. Enter in any fractions using a / (e.g. "1/2" is the sam
mezya [45]

Answer: 2

Step-by-step explanation:

This is a direct proportion. Since y varies as x. This will be:

y = kx

where,

y = 9

x= 3

9 = 3k

k = 9/3

k = 3

Find x when y=6

y = kx

6 = 3x

x = 6/3

x = 2

7 0
3 years ago
One leg of a right triangle measures 6 inches. The remaining leg measures 6 StartRoot 3 EndRoot inches. What is the measure of t
Usimov [2.4K]

Answer:

∅ = 30°

Step-by-step explanation:

given data

side 1 = 6 inches

side 2 = 6\sqrt{3}  inches

to find out

angle opposite the leg that is 6 inches long

solution

we  will use pythagoras theorem that is express as

hypotenuse² = perpendicular²   + base²     .......................1

put here value and we get  hypotenuse

hypotenuse² = 6² + (  )²

solve it we get

hypotenuse²  = 144

hypotenuse = 12 inches  

now we apply here sin∅ that is

sin∅ = \frac{perpendicular}{hypotenuse}     ................2

put here value and we get

put here value and we get

sin∅ = \frac{6}{12}  

∅ = sin^{-1}(0.5)  

solve it we get

∅ = 30°

5 0
3 years ago
Read 2 more answers
When 1250^3/4 is written in its simplest radical form, which value remains under the radical?
castortr0y [4]

Answer:

6 remains under radical

8 0
3 years ago
What are the x intercepts of h(x) in h(x) = -x(x-2)
patriot [66]

Step-by-step explanation:

symbolab would be a great thing to use, itll tell you the steps and the answer

6 0
3 years ago
For triangle ABC with AB=6cm, BC=7cm and BAC=60◦, CA= x cm<br><br>Please show me the process​
Olin [163]
<h2>Answer: X=6.5 cm </h2><h2 />

In order to understand the question and find the solution, let's use the <u>figure attached</u>.

In this figure is shown the triangle with its three sides, where the value of the third is unknown.

We can divide this triangle into two right triangles (figure attached) and use<u> trigonometric functions</u> to find the unknown side in each one:

For Triangle 1:

Is a triangle with sides 6, L and X_{1}. We can use the sine trigonometric function to find side X_{1}:

sin(30\º)=\frac{OS}{H}   (1)

Where OS is the opposite side to the angle and H the hypotenuse

Substituting the values:

sin(30\º)=\frac{ X_{1}}{6cm}

X_{1}=6cm.sin(30\º)

X_{1}=3cm   (2)

For Triangle 2:

We will use the same procedure, nevertheless, in this case the opposite side is X_{2} and the hypotenuse is 7 cm:

sin(30\º)=\frac{ X_{2}}{7cm}

X_{2}=7cm.sin(30\º)

X_{2}=3.5cm   (3)

Adding both values:

X_{1}+ X_{2}=X

We finally find the value of the third side of the whole triangle:

3cm+3.5cm =6.5cm

3 0
3 years ago
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