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ad-work [718]
3 years ago
8

PLEASE HELP!!!

Mathematics
1 answer:
Vikentia [17]3 years ago
4 0

Answer:

Only B is similar

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You have a set of nested boxes whose lengths vary directly with their widths. One box is 2.5 in, wide and 5.5 in. long. A second
Anna11 [10]

Answer:

B

Step-by-step explanation:

If you're looking for direct correlation, you're looking for a proportion for the second box. So you set the ratio of 2.5:5.5 up as a fraction. 2.5/5.5 and set it equal to the second box 3/x.

2.5     =      3

5.5             x

cross multiply

16.5=2.5x

and divide

16.5/2.5 and you get your answer

7 0
3 years ago
17. An equation is shown.
Vladimir [108]
The answer is 1 because 1x7=+7
7 0
3 years ago
Could anyone help me out with this?
Mama L [17]

Answer: they are abt the same its all abt percentage now- Pitcher A

Step-by-step explanation: more water lessens the strength

7 0
3 years ago
I don't know if this is right... please someone help mee
worty [1.4K]
For the first circle, let's use the pythagorean theorem

\bf \textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{8^2+15^2}\implies c=\sqrt{289}\implies c=17

now, it just so happen that the hypotenuse on that triangle, is actually 17, but we used the pythagorean theorem to find it, and the pythagorean theorem only works for right-triangles.

 so if the hypotenuse is actually 17, that means that triangle there is actually a right-triangle, meaning that the radius there, and the outside line there, are both meeting at a right-angle.

when an outside line touches the radius line, and they form a right-angle, the outside line is indeed a tangent line, since the point of tangency is always a right-angle with the radius.



now, let's check for second circle

\bf \textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{11^2+14^2}\implies c=\sqrt{317}\implies c\approx 17.8044938

well, low and behold, we didn't get our hypotenuse as 16 after all, meaning, that triangle is NOT a right-triangle, and that outside line is not touching the radius at a right-angle, therefore is NOT a tangent line.



let's check the third circle

\bf \textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{33^2+56^2}\implies c=\sqrt{4225}\implies c=\stackrel{33+32}{65}

this time, we did get our hypotenuse to 65, the triangle is a right-triangle, so the outside line is indeed a tangent line.
6 0
3 years ago
Quick question
zaharov [31]

Answer:

False

Step-by-step explanation:

Let us evaluate the problem using the proper order of operation:

           4x − 2(5x − 1)

To solve this problem, we use the order of operation called PEMDAS;

P - Parentheses

E - Exponents

M - Multiplication

D - Division

A - Addition

S - Subtraction

Now, since operations inside the parentheses are of the utmost priority, let us solve this;

             4x − 2(5x − 1)

            = 4x - 10x +2

            = -6x + 2  or 2 - 6x

We see that the solution give is false.

7 0
3 years ago
Read 2 more answers
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