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lbvjy [14]
3 years ago
13

Multiplicative inverse of 3/7 x 2/7

Mathematics
2 answers:
Ahat [919]3 years ago
6 0

<h3>\frac{ - 7}{3}  \times  \frac{ - 7}{2}</h3>
  • It is the multiplicative inverse of 3/7 × 2/7
marin [14]3 years ago
5 0

<em>Sorry if I didn't understand the question right-</em>

Answer:

\frac{49}{6}

Step-by-step explanation:

The inverse of \frac{3}{7} is \frac{7}{3}.

The inverse of \frac{2}{7} is \frac{7}{2}.

Now we multiply:

\frac{7}{3} × \frac{7}{2} = \frac{49}{6}

Hope this helped :)

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4) During a school carnival, students from the middle school raised money by selling crafts, food, game tickets, and school play
ioda

$225 was earned from the craft sales

and $40 was earned from the play.

Given, During a school carnival, students from the middle school raised money by selling crafts, food, game tickets, and school play admissions.

Of each dollar earned, $0.15 came from games. Craft sales earned 3 times as much as games. Food sales were 4 times the amount earned from the play.

Let the amount earned by play be x,

Now, Games earned = 0.15×500 = $75

Also, crafts earned 3×75 = $225

Now, as play earned x, then food earned 4x.

According to question,

x + 75 + 225 + 4x = 500

5x + 300 = 500

5x = 200

x = 40

So, the amount earned by Play be, $40

and the amount earned by Food be $160.

Hence, $225 was earned from the craft sales

and $40 was earned from the play.

Learn more about Linear Equations here brainly.com/question/24085666

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5 0
1 year ago
How many different ways can you make 82 cents using current u.s. currency
andrew11 [14]
 <span>You can probably just work it out. 

You need non-negative integer solutions to p+5n+10d+25q = 82. 

If p = leftovers, then you simply need 5n + 10d + 25q ≤ 80. 


So this is the same as n + 2d + 5q ≤ 16 

So now you simply have to "crank out" the cases. 

Case q=0 [ n + 2d ≤ 16 ] 

Case (q=0,d=0) → n = 0 through 16 [17 possibilities] 
Case (q=0,d=1) → n = 0 through 14 [15 possibilities] 
... 
Case (q=0,d=7) → n = 0 through 2 [3 possibilities] 
Case (q=0,d=8) → n = 0 [1 possibility] 

Total from q=0 case: 1 + 3 + ... + 15 + 17 = 81 

Case q=1 [ n + 2d ≤ 11 ] 
Case (q=1,d=0) → n = 0 through 11 [12] 
Case (q=1,d=1) → n = 0 through 9 [10] 
... 
Case (q=1,d=5) → n = 0 through 1 [2] 

Total from q=1 case: 2 + 4 + ... + 10 + 12 = 42 

Case q=2 [ n + 2 ≤ 6 ] 
Case (q=2,d=0) → n = 0 through 6 [7] 
Case (q=2,d=1) → n = 0 through 4 [5] 
Case (q=2,d=2) → n = 0 through 2 [3] 
Case (q=2,d=3) → n = 0 [1] 

Total from case q=2: 1 + 3 + 5 + 7 = 16 

Case q=3 [ n + 2d ≤ 1 ] 
Here d must be 0, so there is only the case: 
Case (q=3,d=0) → n = 0 through 1 [2] 

So the case q=3 only has 2. 

Grand total: 2 + 16 + 42 + 81 = 141 </span>
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kozerog [31]
B, 1.2, is greater in value than 115% 
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Was a major accomplishment of both Tutankhamun and Rameses II.<br><br><br><br><br> Plz help
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Answer:

AA similarity. The angles in both are the same.

Edit: I don't know if you need this, but a major accomplishment of King Tut and Ramses was that they encouraged the following of ancient religious beliefs among the Egyptian people .

Hope that this helps!

6 0
3 years ago
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