All categories

3 years ago

What is 6 divided by 2.99

2 answers:

4 0

Take the 6 divide it by the number 2.99 using a calculator came to 2.01. anything below 4 you leave the number if it ends in 0. if 5 or over you add an additional 1 to the third number in answer.

Mademuasel [1]3 years ago

4 0

2.0066 which is simplified to 2.01

You might be interested in

Find the domain:<br><br> y= <img src="https://tex.z-dn.net/?f=%5Cfrac%7B6%2B9x%7D%7B6-x-1%5C%5C%7D" id="TexFormula1" title="\fra

zavuch27 [327]

Answer:

x= - 0.6

Step-by-step explanation:

<h2 />

3 0

3 years ago

7x + 2 > 30 <br><br> Help please

Alexeev081 [22]

The answer to the question is x > 4

3 0

3 years ago

Read 2 more answers

15 points !!!! Diameter Radius Area Circumference of 84mm

SSSSS [86.1K]

Answer:

$lets \: \: \: find \: \: the \: \: radius \\ = 2\pi \: r \\ = 2\pi \: r = 84 \\ = \frac{2\pi \: r}{2\pi } = \frac{84}{2\pi} \\ = r = 13.37mm$

$lets \: \: \: find \: \: the \: \: \: area \\ = \pi {r}^{2} \\ = \pi \times {13.37}^{2} \\ = 561.55 {mm}^{2}$

$lets \: \: \: find \: \: \: the \: \: diameter \\ = d = 2r \\ = d = 2 \times 13.37 \\ = d = 26.74mm$

6 0

4 years ago

Which number line shows the approximate location of the square root of 10?

Aleks [24]

Answer:

It should be somewhere near 3.16

Step-by-step explanation:

The square root of 10 simplified is around 3.16

5 0

3 years ago

Use matrices to determine the coordinates of the vertices of the reflected figure. Then graph the pre-image and the image on the

Troyanec [42]

Answer:

The coordinates of the vertices of the reflected figure are :

R' is (5 , -2) , S' is (3 , 5) , T' is (-7 , 6) ⇒ the right answer is (d)

Step-by-step explanation:

* When you reflect a point across the line y = x, the x-coordinate

and y-coordinate change their places.

- If the point is (x , y) then its image is (y , x)

* If you reflect over the line y = -x, the x-coordinate and y-coordinate

change their places and their signs

- If the point is (x , y) then its image is (-y , -x)

* Lets study the matrix of the reflection about the line y = x

- The matrix of the reflection about the line y = x is

$\left[\begin{array}{cc}0&1\\1&0\end{array}\right]$

- Because the x-coordinate and y-coordinate change places.

* Now lets solve the problem

- We will multiply the matrix of the reflection about y = x

by each point to find the image of each point

- The dimension of the matrix of the reflection about y = x

is 2×2 and the dimension of the matrix of each point is 2×1,

then the dimension of the matrix of each image is 2×1

∵ The point R is (-2 , 5)

∴ $R'=\left[\begin{array}{cc}0&1\\1&0\end{array}\right]\left[\begin{array}{cc}-2\\5\end{array}\right]=$

$\left[\begin{array}{c}(0)(-2)+(1)(5)\\(1)(-2)+(0)(5)\end{array}\right]=\left[\begin{array}{c}5\\-2\end{array}\right]$

∴ R' is (5 , -2)

∵ The point S is (5 , 3)

∴ $S'=\left[\begin{array}{cc}0&1\\1&0\end{array}\right]\left[\begin{array}{c}5\\3\end{array}\right]=$

$\left[\begin{array}{c}(0)(5)+(1)(3)\\(1)(5)+(0)(3)\end{array}\right]=\left[\begin{array}{c}3\\5\end{array}\right]$

∴ S' is (3 , 5)

∵ The point T is (6 , -7)

∴ $T'=\left[\begin{array}{cc}0&1\\1&0\end{array}\right]\left[\begin{array}{c}6\\-7\end{array}\right]=$

$\left[\begin{array}{c}(0)(6)+(1)(-7)\\(1)(6)+(0)(-7)\end{array}\right]=\left[\begin{array}{c}-7\\6\end{array}\right]$

∴ T' is (-7 , 6)

* Lets look to the figures to find the right answer

∵ The R' is (5 , -2) , S' is (3 , 5) , T' is (-7 , 6)

∴ The right answer is (d)

4 0

3 years ago