<h3>
Answer: -2</h3>
Work Shown:
![f(x) = -2(0.8)^x\\\\f(0) = -2(0.8)^0\\\\f(0) = -2(1)\\\\f(0) = -2\\\\](https://tex.z-dn.net/?f=f%28x%29%20%3D%20-2%280.8%29%5Ex%5C%5C%5C%5Cf%280%29%20%3D%20-2%280.8%29%5E0%5C%5C%5C%5Cf%280%29%20%3D%20-2%281%29%5C%5C%5C%5Cf%280%29%20%3D%20-2%5C%5C%5C%5C)
In the third step, I used the idea that
where x is any nonzero number.
<span>If set X is made up of the possible ways five students, represented by A, B, C, D, and E, can be formed into groups of three, then the set X consists of such triples {ABC, ABD, ABE, ACD, ACE, ADE, BCD, BCE, BDE, CDE} (note that triple ABC is the same as triple ACB, or BCA, or BAC, or CAB, or CBA). The set X totally contains 10 elements (triples). The first statement is true.
</span>
<span>If set
Y is made up of the possible ways five students can be formed into
groups of three if student A must be in all possible groups, then </span><span>the set Y consists of such triples {ABC, ABD, ABE, ACD, ACE, ADE} and contains 6 elements. The second statement is also true.
</span>
<span>If person E must be in each group, then there can be only one group is false statement, because you can see from the set X that triples which contains E are 6.
</span>
<span>There are three ways to form a group if persons A and C must be in it. This statement is true and these groups are ABC, ACD, ACE.</span>
Answer: B) 83%
The chances of winning and the chances of losing add to 100%
So 100% - 17% = 83% is the chances of losing.
This is the 2nd time I've posted this answer... not sure why it didn't go through the first time. Let me know if you have questions. :)