Answer:
Step-by-step explanation:
For a function f to have a maximum as per derivative rule we have to have
f'(x) =0, f"(x) <0
If second derivative =0 also then it is not maximum but point of inflections
Whenever f(x) = ax^n
we have
f'(x) = 0 gives x=0 and
f"(x) = n(n-1) ax ^(n-2)
So for n greater than or equal to there cannot be any maximum
And also for a straight line
y =-4x
y'=-4 and y"-0
No maximum
So only maximum can be for a funciton of the form y = ax^2
Here we do not have that all degrees are either 1 or greater than 1.
So no maximum for any funciton.
3.14=7x-2y
move 7x to the other side
sign changes from +7x to -7x
3.14-7x=7x-7x-2y
3.14-7x=-2y
Divide both sides by -2
3.14/-2-7x/-2=-2y/-2
3.14/-2=-1.57
-7x/-2=7x/2
Answer:
y=-1.57+7x/2
Step-by-step explanation:
Shortest way to solve this question is to find the factors of the given expression.
The given expression is (x² + 13).
Now we have to factorize it.
(x² + 13) = x² + (√13)²
= x² + [-(i)²√(13)²] [Since i = √(-1)]
= x² - (i√13)²
= (x - i√3)(x + i√3) [Since (a² - b²) = (a + b)(a - b)]-by-
Carrie is 2 and Kim is just born.
you can have,
Carrie = 3 4 5 6
Kim = 1 2 3 4
Or something like that, thats a table btw
Answer:
2=|3x|
Step-by-step explanation:
