Answer:
Step-by-step explanation:
Let the no of cars be x and no of buses be y.
x + y = 60 -> y = 60 - x
6x + 30y = 600
with the available equations let us calculate the values of x and y.
6x + 30 * (60-x) = 600
6x + 1800 - 30x = 600
24x = 1200
x cars = 50
y buses = 10
maximum profit = 50 * 2.5 + 10 * 7.5 = $200
Answer:
C
Step-by-step explanation:
Answer:
see below
Step-by-step explanation:
8- 2x - 5- 13x = 6
Combine like terms
-15x+3=6
Subtract 3 from each side
-15x+3-3=6-3
-15x = 3
Divide each side by -15
x = 3/-15
x = -1/5
Check
8 - 2(-1/5) -5 -13(-1/5) = 6
8 + 2/5 -5 +13/5 = 6
3 + 15/5 = 6
3+3=6
6=6
Answer:
10
Step-by-step explanation:
Set up as a proportion:
, insert given values
, cross multiple
36*?=30*12
36*?=360, divide both sides by 36 to get the missing side (?) by itself
?=10
Eq. of line through (1,2) and (4,5) is
x-y+1=0
