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deff fn [24]
3 years ago
11

The auditorium where the spring musical will be performed has 10 seats in the 1st (front) row. Each row behind the Ist row has 4

more seats than does the row in front of it.
how many seats are in the 7th row?
Mathematics
2 answers:
Oksanka [162]3 years ago
7 0
The answer is 38
Explanation.
mafiozo [28]3 years ago
4 0

Answer:

38 seats

Step-by-step explanation:

10 + 4x = y

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Answer:

she needs to sell at least 44 cookies to make a $0.10 profit

Step-by-step explanation:

to find the answer all you have to do is divide 15.30 by 0.35

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1/3 1/4 3/8 7/24 5/12 which is the biggest
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Step-by-step explanation:

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Kim Lu, a data entry clerk, earns $12.25 per hour. She worked 36 hours last week. She also worked 12
lions [1.4K]

Answer:

549

Step-by-step explanation:

Kim Lu, a data entry clerk, earns $12.25 per hour. She worked 36 hours last week. She also worked 12 hours at a part-time job life guarding at $9.00 per hour. What was Kim's total straight-time pay for both jobs?

12.25 * 36 = 441

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3 0
1 year ago
a teacher and 10 students are to be seated along a bench in the bleachers at a basketball game. In how many ways can this be don
Veronika [31]

Wow !

OK.  The line-up on the bench has two "zones" ...

-- One zone, consisting of exactly two people, the teacher and the difficult student.
   Their identities don't change, and their arrangement doesn't change.

-- The other zone, consisting of the other 9 students.
   They can line up in any possible way.

How many ways can you line up 9 students ?

The first one can be any one of 9.   For each of these . . .
The second one can be any one of the remaining 8.  For each of these . . .
The third one can be any one of the remaining 7.  For each of these . . .
The fourth one can be any one of the remaining 6.  For each of these . . .
The fifth one can be any one of the remaining 5.  For each of these . . .
The sixth one can be any one of the remaining 4.  For each of these . . .
The seventh one can be any one of the remaining 3.  For each of these . . .
The eighth one can be either of the remaining 2.  For each of these . . .
The ninth one must be the only one remaining student.

     The total number of possible line-ups is 

               (9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1)  =  9!  =  362,880 .

But wait !  We're not done yet !

For each possible line-up, the teacher and the difficult student can sit

-- On the left end,
-- Between the 1st and 2nd students in the lineup,
-- Between the 2nd and 3rd students in the lineup,
-- Between the 3rd and 4th students in the lineup,
-- Between the 4th and 5th students in the lineup,
-- Between the 5th and 6th students in the lineup,
-- Between the 6th and 7th students in the lineup,
-- Between the 7th and 8th students in the lineup,
-- Between the 8th and 9th students in the lineup,
-- On the right end.

That's 10 different places to put the teacher and the difficult student,
in EACH possible line-up of the other 9 .

So the total total number of ways to do this is

           (362,880) x (10)  =  3,628,800  ways.

If they sit a different way at every game, the class can see a bunch of games
without duplicating their seating arrangement !

4 0
3 years ago
How many laps does it take to walk 1-4 mile
Naddik [55]
Around a track like you run for track meets its 4 so for 1/4 of a mile it would be 1
6 0
3 years ago
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