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stiv31 [10]
3 years ago
12

Trong mặt phẳng tọa độ, viết chương trình đường tròn (C') là ảnh của (C): x^2 +y^2 -2x+4y=0

Mathematics
1 answer:
ryzh [129]3 years ago
3 0

Step-by-step explanation:

Find the properties of the conic section

x

2

+

y

2

−

2

x

+

4

y

x2+y2-2x+4y.0

Center:

(1-2)

Radius:

√5

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aleksandr82 [10.1K]

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subtract 83x from each side

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6 0
3 years ago
A 2.2 kg ball strikes a wall with a velocity of 7.4 m/s to the left. The ball bounces off with a velocity of 6.2 m/s to the righ
Naya [18.7K]

Answer:

The constant force exerted on the ball by the wall is 119.68 N.

Step-by-step explanation:

Consider the provided information.

It is given that the mass of the ball is m = 2.2 kg

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The final velocity of the ball is -6.2 m/s

So the momentum of the ball when it strikes back is = 2.2\times -6.2=-13.64

Thus change in moment is: 16.28-(-13.64)=29.92

The duration of force exerted on the ball t = 0.25 s

Therefore, the constant force exerted on the ball by the wall is:

\frac{29.92}{0.25}=119.68

Hence, the constant force exerted on the ball by the wall is 119.68 N.

6 0
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Answer:

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