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irina1246 [14]
2 years ago
14

HELP PLEASE! Please show work if possible!

Mathematics
2 answers:
Oksana_A [137]2 years ago
7 0
It’s b I did it on paper
Alex777 [14]2 years ago
7 0
The answer is b I just answered this question
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The graph shows the amount of money paid when purchasing bags of candy at the zoo: A graph is shown. The x-axis is labeled from
Zina [86]
I'm positive that it is one 

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3 years ago
Read 2 more answers
This question is WORTH 15 POINTS
masha68 [24]
3x² - 33x - 180 = 0
3(x² - 11x - 60) = 0
3(x² - 15x + 4x - 60) = 0
3(x + 4)(x - 15) = 0
3(x - 4) = 0 or x - 15 = 0
3x - 12 = 0     <u>  + 15  + 15</u>
<u>    + 12 + 12</u>           x = 15
       <u>3x</u> = <u>12</u>
        3      4
         x = 3

The answer is equal to H.15 and E. 4.
8 0
3 years ago
A student takes a driving test until it is passed.
Leya [2.2K]

Answer:

The probability that the test is taken an even number of times is 0.30.

Step-by-step explanation:

The probability that a student passes the driving test at any attempt is,

<em>p</em> = 4/7.

The event of a student passing in any attempt is independent of each other.

The probability that the test is taken an even number of times is:

P (even number of tests) = P (Passing in the 2nd attempt)

                                                  + P (Passing in the 4th attempt)

                                                       + P (Passing in the 6th attempt) ...

If a student passed in the 2nd attempt it implies that he failed in the first.

Then,  P (Passing in the 2nd attempt) = (\frac{3}{7}) \times (\frac{4}{7})

Similarly, P (Passing in the 4th attempt) = (\frac{3}{7})^{3} \times (\frac{4}{7}), since he failed in the first 3 attempts.

And so on.

Compute the probability of an even number of tests as follows:

P (even number of tests) = (\frac{3}{7}) \times (\frac{4}{7})+(\frac{3}{7})^{3} \times (\frac{4}{7})+(\frac{3}{7})^{5} \times (\frac{4}{7})+...

The result follows a Geometric progression for infinite values.

The sum of infinite GP is:

S=\frac{a}{1-r^{2}}

The probability is:

P (even number of tests) = (\frac{3}{7}) \times (\frac{4}{7})+(\frac{3}{7})^{3} \times (\frac{4}{7})+(\frac{3}{7})^{5} \times (\frac{4}{7})+...

                                          =\frac{(\frac{3}{7})(\frac{4}{7} ) }{1-(\frac{3}{7})^{2}}\\=\frac{12}{49}\times\frac{49}{40}\\  =\frac{12}{40}\\ =0.30

Thus, the probability that the test is taken an even number of times is 0.30.

7 0
3 years ago
Determine for what values of x and y are the following equalities always true.
Agata [3.3K]
(k+1)x-(2k+3)y-3k-5=0
kx + x - 2ky - 3y - 3k - 5 = 0
(x - 2y) k + (x - 3y) = 3k + 5

therefore
x - 2y = 3
x - 3y = 5

Subtract 2 equations
y = -2
x = -1
3 0
3 years ago
A circle has a radius of 1 cm. How does the circumference of the circle compare to the area? Drag and drop a phrase to correctly
Lana71 [14]
THE ANSWER IS GREATER THAN I TOOK THIS LESSON!
7 0
3 years ago
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