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ZanzabumX [31]
2 years ago
6

Jeffery is a spelunker. He explores caves. Jeffery has been collecting data on the growth of stalactites over a period of years.

A table of collected data is shown below. Use technology to determine an exponential function to model the data and predict the length of the stalactite after 10 years.

Mathematics
2 answers:
Pepsi [2]2 years ago
7 0

Answer:

The answer is 20.48

Step-by-step explanation:

f(x)=ab^x

y=0.02(2)^x

y=0.02(2)^10

= 20.48

user100 [1]2 years ago
4 0

Answer:

3.12

Step-by-step explanation:

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a jacket cost 4 times as much as a shirt. if the total cost of the jacket and shirt is $280, how much does the shirt cost ------
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3 0
2 years ago
What is -6x+4=-50 and 5x+6=-44 also -3(7+6x)=-201 please solve these equations and show work
grandymaker [24]
Remember you can do anyting to an equation as long as ou do it to both sides



-6x+4=-50
minus 4 both sides
-6x=-54
divide both sides by -6
x=9



5x+6=-44
minus 6 both sides
5x=-50
divide both sides by 5
x=-10


-3(7+6x)=-201
normally you would distribute (that works) but it's easier to divide both sides by -3
7+6x=67
minus 7 both sides
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6 0
3 years ago
A person purchased a slot machine and tested it by playing it 1,137 times. There are 10 different categories of outcomes, includ
ivann1987 [24]

Answer:

p_v= P(\chi^2_{9}>11.517)=0.2419

And on this case if we see the significance level given \alpha=0.1 we see that p_v>alpha so we fail to reject the null hypothesis that the observed outcomes agree with the expected frequencies at 10% of significance.

Step-by-step explanation:

A chi-square goodness of fit test determines if a sample data obtained fit to a specified population.

p_v represent the p value for the test

O= obserbed values

E= expected values

The system of hypothesis for this case are:

Null hypothesis: O_i = E_i[/tex[Alternative hypothesis: [tex]O_i \neq E_i

The statistic to check the hypothesis is given by:

\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

On this case after calculate the statistic they got: \chi^2 = 11.517

And in order to calculate the p value we need to find first the degrees of freedom given by:

df=n-1=10-1=9, where k represent the number of levels (on this cas we have 10 categories)

And in order to calculate the p value we need to calculate the following probability:

p_v= P(\chi^2_{9}>11.517)=0.2419

And on this case if we see the significance level given \alpha=0.1 we see that p_v>alpha so we fail to reject the null hypothesis that the observed outcomes agree with the expected frequencies at 10% of significance.

6 0
3 years ago
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