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2 years ago

A dilation has a center (0,0). Find the image of point B (7/5,-5,4) for the scale factor 1/6

Mathematics

1 answer:

AveGali [126]2 years ago

5 0

Answer:

Multiply the coordinate by the scale factor, 1/5 to get (7/25,-5/20). You can simplify this to (7/25, -1/4)

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PLEASE HELP ASAP<br><br> What is the missing statement for the sixth step in the proof below?

alexira [117]

Answer:

Step-by-step explanation:

The last reasoning is the side angle side theorem. In the whole proof, there is no mention of an angle. So the answer has to involve prooving that the angle in between the two sides that have been proven similar is the same in both traingles. This is best accomplished by statement C.

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2 years ago

Explain the

Ivenika [448]

Answer:

a2=12 (the second term of the sequence is 12)

Step-by-step explanation:

a5=324

If the term to term rule is multiply by any number, we deal with geometrical sequence

The formula you should use is an= a1*r^(n-1) where n is the number of the term which we know. In our case we know

a5, so use 5 instead of n

Then you have a5=a1*r^4 where r is the number 3 (because each next term is greater than previous in 3 times)

a5=324

324= a1*3^4

324=a1*81

a1=4 (We find the first term of sequence, because having it you can easily search for every term )

Return to the formula an= a1*r^n-1

Now search for the second term using 2 instead of n in the formula

a2= a1*r^1

a2=a1*r, a1=4, r=3

a2=4*3=12

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2 years ago

508,372 in word form

Mars2501 [29]

Five hundred and eight thousand three hundred and seventy two

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3 years ago

Which polynomial can be simplified to a difference of squares

Mrrafil [7]

<h2>Hello!</h2>

The answer is:

The polynomial that can be simplified to a difference of squares is the second polynomial:

$16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}=(4-1)(4+1)$

To solve this problem, we need to look for which of the given quadratic terms given for the different polynomials can be a result of squaring (elevating by two).

So,

Discarding, we have:

The quadratic terms of the given polynomials are:

$First=10a^{2}$

$Second=16a^{2}$

$Third=25a^{2}$

$Fourth=24a^{2}$

We have that the coefficients of the quadratic terms that can be obtained by squaring are:

$16a^{2} =(4a)^{2} \\\\25a^{2} =(5a)^{2}$

The other two coefficients are not perfect squares since they can not be obtained by square rooting whole numbers.

So, the first and the fourth polynomial are discarded and cannot be simplified to a difference of squares at least using whole numbers.

Therefore, we need to work with the second and the third polynomial.

For the second polynomial, we have:

$16a^{2} -4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2} =(4-1)(4+1)$

So, the second polynomial can be simplified to a difference of squares.

For the third polynomial, we have:

$25a^{2} +6a-6a+36=16a^{2}+36=(5a)^{2}+(6)^{2}$

So, the third polynomial cannot be simplified to a difference of squares since it's a sum of squares.

Hence, the polynomial that can be simplified to a difference of squares is the second polynomial:

$16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}$

7 0

2 years ago

Read 2 more answers

Which choice is the solution to the inequality below?

Georgia [21]

<h3>hello!</h3>

In order to solve this inequality, we should divide both sides by 9:-

$\sf{9x < 72}$

Why 9? Because x is multiplied by 9, and we need to isolate x in order to find its value.

$\sf{x < 8}$

Hence, that's the solution to the inequality.

<em>It also means that the numbers less than 8 will satisfy the given inequality (make the inequality true)</em>

(Option C is correct :) )

Hope everything is clear; if you need any explanation/clarification, kindly let me know, and I will comment and/or edit my answer :)

8 0

1 year ago

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A dilation has a center​ (0,0). Find the image of point B (7/5,-5,4) for the scale factor 1/6

A dilation has a center (0,0). Find the image of point B (7/5,-5,4) for the scale factor 1/6