❌formed by 2 ions
❌ionic bonds
✅yes because of solvation
✅yes electrolytes are substances that break apart into ions when dissolved
✅in itself but salt water is a good conductor
✅such as water
Answer:
The addition of inorganic phosphate helps to sustain the reaction by helping the reaction to occur in a thermodynamically unfavorable manner.
Explanation:
The reaction of inorganic phosphate with glucose is an endergonic reaction which is thermodynamically unfavorable as a result reaction need coupling of ATP hydrolysis to take place in biological system because ATP hydrolysis releases huge amount of free energy as a result the overall free energy change of this reaction becomes negative which helps the reaction to proceed in a thermodynamically favorable manner.
That"s why inorganic phosphate can be used to sustain the rapidly proceeding glycolysis pathway. The addition of inorganic phosphate makes the reaction thermodynamically unvorable.
Eating, drinking...pretty sure
Answer:
∆H° = 790 kJ/mol
Explanation:
Hello,
In this case, by using the Hess law, we should handle the given reactions as shown below:
- The reaction:
2 Sr(s) + O₂ (g) → 2 SrO (s)
Should be inverted as:
2 SrO (s) → 2 Sr(s) + O₂ (g)
So the enthalpy of reaction changes to ∆H° = 1184 kJ/mol
- The reaction:
CO₂ (g) → C (s) + O₂ (g)
Should be also inverted as:
C (s) + O₂ (g) → CO₂ (g)
So the enthalpy of reaction changes to ∆H° = -394 kJ/mol
- Then, we add the modified reactions to obtain the desired reaction:
2 SrO (s) + C (s) + O₂ (g) → 2 Sr(s) + O₂ (g) CO₂ (g)
C(s) + 2 SrO(s) → CO₂ (g) + 2 Sr(s)
Therefore, the resulting enthalpy of reaction is:
∆H° = 1184 kJ/mol - 394 kJ/mol
∆H° = 790 kJ/mol
Best regards.
Answer:
0.5
Explanation:
2NaCl(s) + 2H2SO4(l) + MnO2(s) → Na2SO4(s) + MnSO4(s) + 2H2O(g) + Cl2(g)
Using ideal gas equation,
PV = nRT
28.7torr
Converting torr to atm,
= 0.0378atm
V = 0.597L
T = 27 °C
= 300 K
a) PV = nRT
(0.0378atm) * (0.597L) = n(0.0821) * (300k)
= 0.000915 mol
moles of water and chlorine = 0.000915 mol
From the above equation, the ratio of water to chlorine = 1 : 2
Therefore, mole of chlorine = 0.000915/2
= 0.000458 mol
mole fraction = moles of specie/moles of all the species present
= 0.000458/0.000915
= 0.5