1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lorasvet [3.4K]
3 years ago
8

A sample of ethanol (C2H6O) has a mass of

Chemistry
1 answer:
Taya2010 [7]3 years ago
4 0

Answer:

-6.517 kJ is the heat of combustion for this sample that is 0.2301 grams of ethanol.

Explanation:

Mass of bomb calorimeter = 2.000 kg = 2.000 × 1000 g = 2000. g

1 kg = 1000 g

Specific heat of bomb  calorimeter = c = 2.45 J/g°C

Change in temperature = \Delta T=1.33^oC

Heat absorbed by the bomb claorimeter = Q

Q=m\times c\times \Delta T

=2000 g\times 2.45 J/g^oC\times 1.33^oC=6,517 J

Heat energy released on combustion of 0.2301 grams of ethanol = Q'= -Q

Q' = -Q = -6,517 J = -6.517 kJ

1 J = 0.001 kJ

-6.517 kJ is the heat of combustion for this sample that is 0.2301 grams of ethanol.

You might be interested in
Which type of scientist would most likely study how electricity could be
Nikolay [14]

Electrical engineers are the scientists that study the production of electricity more efficient.

<h3>Which type of scientist would study how electricity could be produced more efficiently?</h3>

Electrical engineers are the type of scientist that would most likely study how electricity could be produced more efficiently because they produced new technologies which are cost efficient as well as produce high amount of electricity.

So we can conclude that electrical engineers are the scientists that study the production of electricity more efficient.

Learn more about electricity here: brainly.com/question/776932

#SPJ1

6 0
2 years ago
There are 15 technicians and 11 chemists working in a research laboratory. In how many ways could they form a 5-member safety co
Fynjy0 [20]

a)

26C5 -> 26 choices of 5 things

b)

15C1 × 11C4

c)

11C1 × 15C4

d)

11C2 × 15C2

e)

11C4

or

15C4

5 0
3 years ago
In a chemical reaction, __________ are the substances present after the reaction.
chubhunter [2.5K]

Answer:

products

Explanation:

4 0
3 years ago
Read 2 more answers
Calculate the molarity of 8.42 x 102 mL of solution containing 22.4 g of potassium iodide.
givi [52]

Answer:

Molarity = 0.154 M

Explanation:

Given data:

Volume of solution = 8.42 × 10² mL ( 8.42 × 10² /1000 = 0.842 L)

Mass of potassium iodide = 22.4 g

Molarity of solution = ?

Solution:

Number of moles of potassium iodide:

Number of moles = mass/molar mass

Number of moles = 22.4 g/ 166.0 g/mol

Number of moles = 0.13 mol

Molarity:

Molarity = number of moles / volume in L

Molarity = 0.13 mol / 0.842 L

Molarity = 0.154 M

8 0
3 years ago
What factors trigger the evolution of a species?
lozanna [386]
Humans opinions of evolution.
7 0
4 years ago
Read 2 more answers
Other questions:
  • Are the properties of sodium and chlorine the same as sodium chloride
    12·1 answer
  • Arrange these compounds by their expected vapor pressure: H2O NCl3 Br2
    7·1 answer
  • Is this statement true or false? Oil and natural gas are fuel resources harvested from the ocean.
    14·2 answers
  • Which of the following pairs of atoms exhibit an ionic bond?
    13·2 answers
  • Explain how an equation can be balanced even if the number of reactant particles differs from the number of product particles
    8·1 answer
  • Which molecule, when added to a solution, would give the solution the highest pH?
    9·1 answer
  • A 35.00 mL sample of an H2SO4 solution of unknown concentration is titrated with a 0.1222 M KOH solution. A volume of 42.22 mL o
    7·1 answer
  • After reviewing your answers to questions 2 and 4 above, would you define boiling point and melting point as a periodic table fa
    15·1 answer
  • At what temperature do NaNO3 and KNO3 have the same solubility?
    8·1 answer
  • Brainliest fast before 5:35 no link no bot
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!