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Andreyy89
3 years ago
12

Emilio compra 3,6 kg de manzanas a 1,45 euros el kilo ¿Cuánto pagara por las manzanas?

Mathematics
1 answer:
Ad libitum [116K]3 years ago
3 0

Answer:

Emilio compra kg De manzanas a euros el kilo cuanto pagara por Las manzanas

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Answer:

b

Step-by-step explanation:

6 0
3 years ago
Find the area of a regular hexagon if given a side length of 1.9 to the square root of 3.
dalvyx [7]

Answer:

28.137 sq. units.

Step-by-step explanation:

Area of a regular hexagon is

A=\dfrac{3\sqrt{3}}{2}a^2

where, a is the side length.

It is given that the side length of the regular hexagon is 1.9\sqrt{3}.

Substitute a=1.9\sqrt{3} in the above formula.

A=\dfrac{3\sqrt{3}}{2}(1.9\sqrt{3})^2

A=(1.5\sqrt{3})(10.83)

A=16.245\sqrt{3}

A=28.137

Therefore, the area of regular hexagon is 28.137 sq. units.

6 0
3 years ago
A plane takes off from an airport and flies at a speed of 400km/h on a course of 120° for 2 hours. the plane then changes its co
butalik [34]

Answer:

Distance from the airport = 894.43 km

Step-by-step explanation:

Displacement and Velocity

The velocity of an object assumed as constant in time can be computed as

\displaystyle \vec{v}=\frac{\vec{x}}{t}

Where \vec x is the displacement. Both the velocity and displacement are vectors. The displacement can be computed from the above relation as

\displaystyle \vec{x}=\vec{v}.t

The plane goes at 400 Km/h on a course of 120° for 2 hours. We can compute the components of the velocity as

\displaystyle \vec{v_1}=

\displaystyle \vec{v_1}=\ km/h

The displacement of the plane in 2 hours is

\displaystyle \vec{x_1}=\vec{v_1}.t_1=.(2)

\displaystyle \vec{x_1}=km

Now the plane keeps the same speed but now its course is 210° for 1 hour. The components of the velocity are

\displaystyle \vec{v_2}=

\displaystyle \vec{v_2}=km/h

The displacement in 1 hour is

\displaystyle \vec{x_2}=\vec{v_2}.t_2=.(1)

\displaystyle \vec{x_2}=km

The total displacement is the vector sum of both

\displaystyle \vec{x_t}=\vec{x_1}+\vec{x_2}=+

\displaystyle \vec{x_t}=km

\displaystyle \vec{x_t}=

The distance from the airport is the module of the displacement:

\displaystyle |\vec{x_t}|=\sqrt{(-746.41)^2+492.82^2}

\displaystyle |\vec{x_t}|=894.43\ km

8 0
4 years ago
Help please i have 0 clue on what to do
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Answer:

Step-by-step explanation:

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3 years ago
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"to find x in part a, you would need" to solve the equation x 2 – 25 =0. wh
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X2 - 25 = 0

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