If it reaches its maximum height a t=3 its velocity must be zero at t=3
dy/dx=0 at t=3
dA/dx=4x+12=24 at t=3 so this does not apply
dB/dx=-4x+12=0 at t=3 and B=13 at t=3 so B applies
dC/dx=-4x-12=-24 at t=3 so this does not apply
dD/dx=-4x-12=-24 at t=3 so this does not apply
dE/dx=-4x-12=-24 at t=3 so this does not apply
So only quadratic B: reaches a maximum height of 13 feet at 3 seconds.
1. 567
2. 33
3. 85%; $17
4. they have 4 pages left
5. (-5,2)
Call M the midpoint. The coordinate of this point is given by....
M=(x1+x2 /2, y1+y2 /2)
So (3,7)=(x1+0 /2, y1+ -5 /2). or
3= x1/2. or x1=6 and
7=y1-5 /2. or 14=y1-5 or y1=19
B is at the point (6,19)
Answer:
See proof below
Step-by-step explanation:
We have to verify that if we substitute 
in the equation 
the equality is true.
Let's substitute first in the right hand side:
Now we use the distributive laws. Also, note that 
(this also works when the power is n-2).
then the sequence solves the recurrence relation.
