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Alchen [17]
2 years ago
11

Lou ​'s car had 6.8 gallons in the ​16-gallon tank on the coldest day of the year. Lou filled the tank with gas that cost ​$3.90

per gallon. How much did Lou spend on​ gas?
Mathematics
1 answer:
vodka [1.7K]2 years ago
5 0

Answer: 35.88

Step-by-step explanation:

first :  16 - 6.8

then : 9.2 x 3.90

last : your answer should be 35.88 , thank you and hope you finish well .

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Solve the proportion below. 5/x = 30/72 a.12 b.9 c.6 d.30
AnnyKZ [126]

Answer:

A. 12

Step-by-step explanation:

Cross multiply:

30x = 72(5)

x = 360/30

x = 12

3 0
3 years ago
Read 2 more answers
PLZ ANSWER QUICK IT WILL HELP A LOT!
natima [27]

Answer:

B

Step-by-step explanation:

But I don’t really know I struggle with this

5 0
3 years ago
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I got ALL of the answers but I can't explain it at all... please explain guys I have NO idea!
nekit [7.7K]

Explanation:

The altitude CH divides triangle ABC into similar triangles:

ΔABC ~ ΔACH ~ ΔCBH

Angle bisector AL divides the triangle(s) into proportional parts:

BL/BA = CL/CA

HD/HA = CD/CA

Of course, the Pythagorean theorem applies to the sides of each right triangle:

AH^2 +CH^2 = AC^2

DH^2 +AH^2 = AD^2

LC^2 + AC^2 = LA^2

AC^2 +BC^2 = AB^2

And segment lengths sum:

HD +DC = HC

AD +DL = AL

AH +HB = AB

CL +LB = CB

Solving the problem involves picking the relations that let you find something you don't know from the things you do know. You keep going this way until the whole geometry is solved (or, at least, the parts you care about).

___

We can use the Pythagorean theorem to find AH right away, since we already know AD and DH.

DH^2 +AH^2 = AD^2

4^2 + AH^2 = 8^2 . . . . . . . substitute known values

AH^2 = 64 -16 = 48 . . . . . . subtract 16

AH = 4√3 . . . . . . . . . . . . . . take the square root

Now, we can use this with the angle bisector relation to tell us how CD and CA are related.

HD/HA = CD/CA

4/(4√3) = CD/CA . . . . . substitute known values

CA = CD·√3 . . . . . . . . . cross multiply and simplify

Using the sum of lengths equation, we have ...

CH = HD +CD

CH = 4 + CD

From the Pythagorean theorem ...

AH^2 +CH^2 = AC^2

(4√3)^2 + (4 +CD)^2 = (CD√3)^2 . . . . . substitute known values

48 + (16 +8·CD +CD^2) = 3·CD^2 . . . . . simplify a bit

2·CD^2 -8·CD -64 = 0 . . . . . . . . . . . . . . . put the quadratic into standard form

2(CD -8)(CD +4) = 0 . . . . . . . . . . . . . . . . factor

CD = 8 . . . . . only the positive solution is useful here

Now, we know ...

∆ADC is isosceles, so ∠ACH = ∠CAD = ∠DAH = ∠CBA

CH = 8+4 = 12

AC = 8√3 . . . . . = 2·AH

Then by similar triangles, ...

AB = 2·AC = 16√3

BC = AC·√3 = 24

7 0
3 years ago
What weight is equivalent to 40 ounces
vaieri [72.5K]

Answer:

40 ounces = 2.5 pounds

Step-by-step explanation:

divide the mass by 16.

6 0
3 years ago
What is the value of x
aivan3 [116]
The original value of x was negative, then –x, the opposite-signed version of x, would have to be positive. For instance, if I start with x = –3, then –x = –(–3) = +3, which is positive.
8 0
3 years ago
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