All categories

2 years ago

Solve the attached question .No Spam!Step by step explanation needed!

Mathematics

2 answers:

Kisachek [45]2 years ago

3 0

Your answer is attached.

Hence, COT A (Option A) is the right answer.

Hope it helps uh!

Luba_88 [7]2 years ago

3 0

Answer to your question is given in the attachment

<h3>HOPE THIS HELPS </h3>

You might be interested in

Write the standard form for the scientific notation. please help fast!!!

jarptica [38.1K]

$2.32\cdot10^3=2.32\cdot1,000=2,320\\\\4.2\cdot10^4=4.2\cdot10,000=42,000\\\\4.2\cdot10^{-2}=4.2\cdot0.01=0.042$

Multiplication by 10ⁿ → move decimal n places to the right.

Multiplication by 10⁻ⁿ → move decimal n places to the left.

For n ∈ N

6 0

2 years ago

Which of the following statements is TRUE? You cannot choose the Economy Plan if you have a family. You can choose to opt out of

xxTIMURxx [149]

The statement which is true is; You can choose to opt out of any health care, vision coverage, and/or dental coverage included in the Standard Plan described in the Medical Plan documents.

<h3>Medical plans</h3>

In partial fulfillment of exercising one's human rights, an individual can choose to opt out of any healthcare, vision coverage, and/or dental coverage included in the Standard Plan described in the Medical Plan documents.

However, there are consequences for not having medical plans.

Read more on medical plans;

brainly.com/question/25793763

3 0

2 years ago

Discrete R.V. Assume a student shows up for EGR 280 completely unprepared and the instructor gives a pop quiz. Assume there are

Tom [10]

Answer:

a) p=0.2

b) probability of passing is 0.01696

c) The expected value of correct questions is 1.2

Step-by-step explanation:

a) Since each question has 5 options, all of them equally likely, and only one correct answer, then the probability of having a correct answer is 1/5 = 0.2.

b) Let X be the number of correct answers. We will model this situation by considering X as a binomial random variable with a success probability of p=0.2 and having n=6 samples. We have the following for k=0,1,2,3,4,5,6

$P(X=k) = \binom{n}{k}p^{k}(1-p)^{n-k} = \binom{6}{k}0.2^{k}(0.8)^{6-k}$ .

Recall that $\binom{n}{k}= \frac{n!}{k!(n-k)!}$ In this case, the student passes if X is at least four correct questions, then

$P(X\geq 4) = P(X=4)+P(X=5)+P(X=6)=\binom{6}{4}0.2^{4}(0.8)^{6-4}+\binom{6}{5}0.2^{5}(0.8)^{6-5}+\binom{6}{6}0.2^{6}(0.8)^{6-6}= 0.01696$

c)The expected value of a binomial random variable with parameters n and p is $E[X] = np$ . IN our case, n=6 and p =0.2. Then the expected value of correct answers is $6\cdot 0.2 = 1.2$

5 0

3 years ago

A ball is thrown into the air with a velocity of 34 ft/s. It's height in feet after t seconds is given by y=34t-26(t)^2. Find th

kkurt [141]

Answer:

The average velocity of the ball at the given time interval is -122.3 ft/s

Step-by-step explanation:

Given;

velocity of the ball, v = 34 ft/s

height of the ball, y = 34t - 26t²

initial time, t₀ = 3 seconds

final time, t = 3 + 0.01 = 3.01 seconds

At t = 3 s

y(3) = 34(3) - 26(3)² = -132

The average velocity of the ball in ft/s is given as;

$V_{avg} = \frac{y(3.01)-y(3)}{3.01 -3}\\\\V_{avg} = \frac{34(3.01)-26(3.01)^2-y(3)}{3.01 -3}\\\\V_{avg} = \frac{-133.223-y(3)}{0.01}\\\\V_{avg} = \frac{-133.223-(-132)}{0.01}\\\\V_{avg} =\frac{-1.223}{0.01}\\\\V_{avg} = -122.3 \ ft/s$

Therefore, the average velocity of the ball at the given time interval is -122.3 ft/s

8 0

3 years ago

HELPP ILL HIVE BRAINLIEST

UkoKoshka [18]

Answer:

part a: two is the y intercept because the line intercepts at two on the y-axis

part b: i don't know but gl

6 0

2 years ago

Solve the attached question .No Spam!Step by step explanation needed!​

Solve the attached question .No Spam!Step by step explanation needed!