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2 years ago

What is the difference between the largest prime number less than 5o and the smallest comoosite number greater than 10

Mathematics

1 answer:

erastova [34]2 years ago

8 0

<h3>Answer: 35</h3>

A prime number is one where the only factors are one and itself. A composite number has other factors.

You'll have to look at the list of numbers from 1 to 50

In that list, 47 is the largest prime less than 50, and 12 is the smallest composite number greater than 10.

So 47-12 = 35

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What Values of X will make x2 (Exponent of 2) =16 true? HELPPPPPP!!

Lynna [10]

Answer:

Step-by-step explanation:

Given

x² = 16 ( take the square root of both sides )

$\sqrt{x^2}$ = ± $\sqrt{16}$ ← note plus or minus sign

x = ± 4

Since 4² = 4 × 4 = 16 and

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3 years ago

onji has $5.25 in nickels and dimes.The coin value can be modeled by the equation 0.10d + 0.05n = 5.25, where d represents the n

Maru [420]

This is how you solve this problem:
.10d + .05n = 5.25

(plug in the number of dimes we have)

(21 x .1) + .05n = 5.25

(multiply number of dimes x value of the dime)

2.10 + .05n = 5.25

(subtract 2.10 from both sides)

.05n = 3.15

(divide both sides by .05 to get the number of nickels)

n = 63 nickels

Hope this helps!

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3 years ago

Can someone solve this?

aleksley [76]

Answer:

Considering the Law of Cosines:

$c^2=a^2+b^2-2ab*cosC$

$a=14mi; b=24mi; c=CA; C=91degrees$

$\cos \left(91^{\circ \:}\right)=-0.01745\dots$

$c^2=14^2+24^2-2(14)(24)*\cos \left(91^{\circ \:}\right)\\c^2=196+576-672*\cos \left(91^{\circ \:}\right)\\c^2=772-672*\cos \left(91^{\circ \:}\right)\\c^2=772-672*(-0.01745)\\c^2=772+11.7264\\c=\sqrt{772+11.7264} \\c=\sqrt{783.7264}\\c=27.99mi$

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3 years ago

What is formula in your own words?

geniusboy [140]

A mathematical relationship or a rule mostly expressed in symbols

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2 years ago

Can you help me i dont know thw anwser

Margaret [11]

$\text{Let the side of square 1, square 2 and square 3 be x, y and z respectively.}\\\\\text{Given that,}\\\\\text{Perimeter of square 1,~~ p =100 units.}\\\\\text{So}~ x=\dfrac p 4 = \dfrac{100}4 =25~\text{units.}\\\\\\\text{Area of square 2, a = 225 units}^2\\\\\text{So}~y = \sqrt{a} = \sqrt {225} = 15~ \text{units.}\\\\\text{Use Pythagorean theorem to find z}^2\\\\x^2 =y^2 +z^2 \\\\\implies 25^2 = 15^2 +z^2\\\\\implies z^2 = 625 - 225 = 400\\\\\\$

$\text{Hence the area of square 3 is 400 units}^2.$

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2 years ago

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