1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jarptica [38.1K]
3 years ago
12

What is the difference between the largest prime number less than 5o and the smallest comoosite number greater than 10

Mathematics
1 answer:
erastova [34]3 years ago
8 0
<h3>Answer:  35</h3>

A prime number is one where the only factors are one and itself. A composite number has other factors.

You'll have to look at the list of numbers from 1 to 50

In that list, 47 is the largest prime less than 50, and 12 is the smallest composite number greater than 10.

So 47-12 = 35

You might be interested in
If Ryuk eats 7 apples for every 50 names Light writes in the death note, how many apples will he have eaten after Light writes 5
alex41 [277]

Answer:

70 apples

Step-by-step explanation:

We can use a ratio to solve

7 apples        x apples

--------------  = -------------

50 name     500 names

Using cross products

7 * 500 = 50x

Divide by 50

7 * 500/50 = 50x/50

70 =x

6 0
3 years ago
Read 2 more answers
Describe how to use a tens fact to find the difference for 15-8
scoundrel [369]
Because you need to subtract from 10, you need to do 10-8. Then you will add 5 since you took away 5 to subtract from 10.
8 0
3 years ago
Read 2 more answers
What value of x makes this equation true? 15-7x=5x-21​
belka [17]

Answer:

x=3

Step-by-step explanation:

15-7x=5x-21

12x=36

x=3

4 0
3 years ago
A particle is moving along the x-axis so that its position at t ≥ 0 is given by s(t)=(t)ln(5t). Find the acceleration of the par
lyudmila [28]

Answer:

a(\frac{1}{5e})=5e

Step-by-step explanation:

we are given equation for position function as

s(t)=tln(5t)

Since, we have to find acceleration

For finding acceleration , we will find second derivative

s'(t)=\frac{d}{dt}\left(t\ln \left(5t\right)\right)

=\frac{d}{dt}\left(t\right)\ln \left(5t\right)+\frac{d}{dt}\left(\ln \left(5t\right)\right)t

=1\cdot \ln \left(5t\right)+\frac{1}{t}t

s'(t)=\ln \left(5t\right)+1

now, we can find derivative again

s''(t)=\frac{d}{dt}\left(\ln \left(5t\right)+1\right)

=\frac{d}{dt}\left(\ln \left(5t\right)\right)+\frac{d}{dt}\left(1\right)

=\frac{1}{t}+0

a(t)=\frac{1}{t}

Firstly, we will set velocity =0

and then we can solve for t

v(t)=s'(t)=\ln \left(5t\right)+1=0

we get

t=\frac{1}{5e}

now, we can plug that into acceleration

and we get

a(\frac{1}{5e})=\frac{1}{\frac{1}{5e}}

a(\frac{1}{5e})=5e


5 0
3 years ago
Kenji's electricity bill costs $21.56 per month plus $2.46 per kilowatt hour. How many kilowatt hours can he use and keep his bi
Alik [6]

Answer:

Kenjii can use 13.19 kilowatt-hour.

Step-by-step explanation:

Giving the following information:

Kenji's electricity bill costs $21.56 per month plus $2.46 per kilowatt-hour.

<u>First, we will structure the total cost formula:</u>

Total cost= 21.56 + 2.46*x

x= kilowatt-hour

54= 21.56 + 2.46x

32.44= 2.46x

13.19= x

Kenjii can use 13.19 kilowatt-hour.

5 0
3 years ago
Other questions:
  • Find the sum of 86331 and 909
    10·1 answer
  • A new piece of equipment costs $18,000 with a residual value of $600 and an estimated useful life of
    11·1 answer
  • A movie cost $3,254,107 to produce. What digit is in the hundred thousands place?
    15·1 answer
  • 77+ 2(3x – 5) = 8 – 3(2x + 1)<br> 78 2 + 3(2 -7) – 0 - 13 I 1).
    5·1 answer
  • A line passes through the point , 9,−2 and has a slope of 4/3. Write an equation in point-slope form for this line.
    14·2 answers
  • Yep here we go again:
    13·2 answers
  • Pleaseeeee help ill give brainliest answerrrrr
    12·1 answer
  • PLEAAASE HELP ILL MARK BRAINLIEST
    12·2 answers
  • Please help me with this question!!
    14·1 answer
  • 3. Jessie has 25 small
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!