X^3+3x^2-18x-3x^2-9x+54
————-
Final answer=
X^3-27x+54
I hope you understand my explanation and best of wishes!!
To find f'(3) (f prime of 3), you must find f' first. f' is the derivative of the function f(x).
Finding the derivative of f(x) = 2x⁴ requires the use of the power rule.
The power rule for derivatives is ![\frac{d}{dx} [x^{n} ] =nx^{n-1}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bx%5E%7Bn%7D%20%5D%20%3Dnx%5E%7Bn-1%7D)
. In other words, you bring the exponent forward and multiply it by the coefficient of the term, and then you subtract 1 from the original exponent.
f'(x) = 
(2x⁴)
f'(x) = 2(4)x³
f'(x) = 8x³
Now, to find f'(3), plug 3 into your derivative.
f'(3) = 8(3)³
f'(3) = 216
<h3>Answer:</h3>
f'(3) = 216
Answer:
240
Step-by-step explanation:
240 + 60 = 300 you can tell this by realising that ratio to have 4x one over the other would be 20 per 100, using this rate 3x, 240 and 60
Answer:
20 Divided By 5 = 4 or 5 x4 = 20
Step-by-step explanation:
Where's the net. We need the net to answer the question
