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3 years ago

6+\sqrt{6-15x}=15 Solve the radical

Mathematics

2 answers:

Allisa [31]3 years ago

8 0

Answer:

$x=-5$

Step-by-step explanation:

$6+\sqrt{6-15x}=15$

Subtract 6 from both sides of the equation:

$6+\sqrt{6-15x}-6=15-6$

Subtract 6 from itself which will give you 0.

$\sqrt{-15x+6}=15-6$

Subtract 6 from 15 :

$\sqrt{-15x+6}=9$

Square both sides of the equation:

$-15x+6=81$

Subtract 6 from both sides of the equation:

$-15x+6-6=81-6$

$-15x=81-6$

Subtract 6 from 81:

$-15x=75$

Divide both sides by -15:

$\frac{-15x}{-15} =\frac{75}{-15}$

$x=-5$

___________________________

Airida [17]3 years ago

5 0

Answer:

$x=-5$

Thank you.....

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Answer:

$\textsf{12.} \quad y = 6x - 5$

$\textsf{17.} \quad y=-\dfrac{1}{4}x-2$

Step-by-step explanation:

<h3>Question 12</h3>

Find the slope of the line by substituting two points from the given table into the slope formula.

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Let (x₁, y₁) = (2, 7)
Let (x₂, y₂) = (3, 13)

$\implies \textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{13-7}{3-2}=\dfrac{6}{1}=6$

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<h3>Question 17</h3>

Given:

f(4) = 3
f(0) = -2

Therefore, two points on the line are:

(4, -3)
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The y-intercept is the y-value when x = 0.

Therefore, the y-intercept of the line is -2.

$\boxed{\begin{minipage}{6.3 cm}\underline{Slope-intercept form of a linear equation}\\\\$y=mx+b$\\\\where:\\ \phantom{ww}$\bullet$ $m$ is the slope. \\ \phantom{ww}$\bullet$ $b$ is the $y$-intercept.\\\end{minipage}}$