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Serhud [2]
4 years ago
5

A scooter manufacturer makes two types of scooters: the Go-go, which sells for $3,200 and the Whip sells for $5,000. Both models

use the same frame, but the painting and assembly time required for the Go-go is 3 hours, while the time is 6 hours for the Whip. Each day, the company produces 120 frames, and has 600 hours of labor available for production. How many of each model should be produced to maximize revenue?
Mathematics
2 answers:
uysha [10]4 years ago
8 0

Answer:

the answer is c

Step-by-step explanation:

garik1379 [7]4 years ago
4 0
Let the number of Go-go scooter to be produced be x and that of Whip scooter y, then
Maximize: R = 3200x + 5000y
subject to:
x + y ≤ 120
3x + 6y ≤ 600
The corner points of the constraints are (0, 0), (0, 100), (40, 80), (120, 0)
For (0, 0): R = 0
For (0, 100): R = 3200(0) + 5000(100) = 500,000
For (40, 80): R = 3200(40) + 5000(80) = 528,000
For (120, 0): R = 3200(120) + 5000(0) = 384,000

Therefore, for maximum revenue, they should produce 40 Go-go scooters and 80 Whip scooters.
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