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Anna71 [15]
1 year ago
10

Solve the equation on the interval [0,2π). 2 sin x -1=0

Mathematics
1 answer:
Nataly [62]1 year ago
3 0

sgdhrjdjfjfj

Step-by-step explanation:

gkgzzggzgzzggzgzgzgz

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Write an equation to express the relationship between pressure and temperture (k) use the symbols p,t,k
IRISSAK [1]
K = constant

k * temperature = pressure

or p/t = k

this is gay-lussac's law. are you using temperature in kelvin or is that a mistake while writing the question?
6 0
3 years ago
What is 2 ^ 4 in standard form?​
spin [16.1K]
6x=10^= (*=0) is the answer
3 0
3 years ago
A restaurant customer left ​$1.65 as a tip. The tax was 4 % and the tip was 15​% of the after tax cost. Which information is not
Fed [463]
You dont need the percentage of tip. to calculate the bill, divide 100 by 15, then multiply that number by 1.65, you will get the total of the bill afer tax. if you add 1.65 to the total you get the total after tax and tip
8 0
3 years ago
HELP PLEASEEE
djyliett [7]

Answer:

Exact circumference is 7\frac{49}{150}km

Approximate circumference is 7.33 km

Step-by-step explanation:

We are given;

  • The diameter of a circle as 2\frac{1}{3} km

We are required to determine the exact and approximate circumference of the circle.

  • We know that the circumference of the circle is given by;
  • Circumference = πD, where D is the diameter

Taking π as 3.14

Circumference=3.14 (2\frac{1}{3}km)

                          =7\frac{49}{150}km

The exact circumference of the circle is 7\frac{49}{150}km

7\frac{49}{150}km=7.327 km\\                            = 7.33 km (nearest hundredth)

Thus, the approximate circumference of the circle is 7.33 km

6 0
3 years ago
For each part of this problem, show all your work and write a probability statement.
AlladinOne [14]

Answer:

Follows are the answer to the given point.

Step-by-step explanation:

In point 1:

\to P( \text{number of response}) = \frac{192}{338} \\

                                        = \frac{96}{169}\\\\= 0.56

In point 2:

\to P| \text{(Zoloft and fill response)}| = \frac{27}{338}

                                                 = 0.079

In point 3:

\to P(\frac{\text{ full or partial}}{\text{St. John's Wort}}) = \frac{\frac{43}{338}}{\frac{113}{338}}

                                = \frac{43}{338} \times \frac{338} {113}\\\\= \frac{43}{113}\\\\= 0.38

In point 4:

\to P(\frac{\text{Placebo}}{\text{full or response}}) = P(\frac{(\text{Placebo} \cap \text{full or response})} {\text{p(full response)}})

                               = \frac{\frac{79}{338}}{ 1- \frac{91}{338}} \\\\ = \frac{\frac{79}{338}}{  \frac{338-91}{338}} \\\\  = \frac{\frac{79}{338}}{\frac{247}{338}} \\\\  = \frac{79}{338} \times \frac {338}{247} \\\\= \frac{79}{274} \\\\ = 0.28

4 0
3 years ago
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