1 year ago

Solve the equation on the interval [0,2π). 2 sin x -1=0

Mathematics

1 answer:

Nataly [62]1 year ago

3 0

sgdhrjdjfjfj

Step-by-step explanation:

gkgzzggzgzzggzgzgzgz

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40 or $2\sqrt{10}$

Step-by-step explanation:

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sveticcg [70]

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B. equivalent

Step-by-step explanation:

Our two equations are:

$y=-\frac{1}{3} x +\frac{2}{3}$

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Let's use substitution and plug in the expression $-\frac{1}{3} x +\frac{2}{3}$ for y in the second equation. That way, we're getting rid of a variable so we can solve for the other:

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