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likoan [24]
3 years ago
8

POSTING THIS AGAIN PLEASE I NEED HELP I CAN'T FAIL THIS TEST

Mathematics
1 answer:
kotegsom [21]3 years ago
4 0

Answer:

729 : 9 = 80 +1 is correct

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How do you solve this ?
ss7ja [257]

Answer:

q=7.7

Step-by-step explanation: This is trigonometry and you would use cosine since you have H (29) as your known and A (q) as your unknown. You would do cos(39)29=7.7

4 0
3 years ago
How would I do part A. I showed my work but I'm slightly off
ahrayia [7]

\bf \stackrel{\textit{perimeter of the rectangle}}{P_{rect}=2x+y}~\hfill \stackrel{\textit{area of the rectangle}}{A_{rect}=xy}
\\\\\\
\stackrel{\textit{perimeter of the semi-circle, with }r=\frac{y}{2}}{P_{semic}=\cfrac{\pi y}{2}}~\hfill \stackrel{\textit{area of the semi-circle with }r=\frac{y}{2}}{A_{semic}=\cfrac{\pi y^2}{8}}
\\\\[-0.35em]
\rule{34em}{0.25pt}


\bf \stackrel{\textit{perimeter of the enclosure}}{60=2x+y+\cfrac{\pi y}{2}}\implies \stackrel{\textit{multiplying by 2}}{120=4x+2y+\pi y}
\\\\\\
120-2y-\pi y=4x\implies \cfrac{120-2y-\pi y}{4}=x
\\\\[-0.35em]
\rule{34em}{0.25pt}


\bf \stackrel{\textit{area of the enclosure}}{A=xy+\cfrac{\pi y^2}{8}}\implies A=\left( \cfrac{120-2y-\pi y}{4} \right)y+\cfrac{\pi y^2}{8}
\\\\\\
A=\cfrac{120y-2y^2-\pi y^2}{4}+\cfrac{\pi y^2}{8}\implies A=\cfrac{240y-4y^2-2\pi y^2+\pi y^2}{8}
\\\\\\
A=\cfrac{240y-4y^2-\pi y^2}{8}\implies A=\cfrac{240y}{8}-\cfrac{4y^2}{8}-\cfrac{\pi y^2}{8}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
~\hfill A=30y-\cfrac{1}{2}y^2-\cfrac{1}{8}\pi y^2~\hfill

5 0
3 years ago
Find the equation of the line that contains the point (21,27) and is parallel to the x-axis.
Stells [14]

Answer:

y - 27 = 0 (x - 21) or y = 27

Step-by-step explanation:

8 0
3 years ago
In this figure
alina1380 [7]

Answer:

∠y = 62.5°

∠x  =  27.5°

Step-by-step explanation:

z is right angle. ∠z = 90°

∠x = ∠y - 35

∠x + ∠y + ∠z = 180      {Angle sum property of triangle}

y - 35 + y + 90 = 180

y + y - 35 + 90 = 180 {Combine like terms}

  2y  + 55 = 180

          2y = 180 -55      {Subtract 55 from both sides}

          2y = 125         {Divide both sides by 2}

            y = 125 /2

∠y = 62.5°

∠x = 62.5 - 35 = 27.5°

6 0
3 years ago
Please help! This is for Algebra 1
kow [346]
The first answer
-40y3/x5
8 0
3 years ago
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