3 years ago

What does the line x=-5 look like

Mathematics

2 answers:

Slav-nsk [51]3 years ago

6 0

A vertical line that passes through (-5,0)

Papessa [141]3 years ago

5 0

A straight line going vertical on the left side of the graph

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Please for brainliest do it as quick as possible

nika2105 [10]

Answer:

Step-by-step explanation:

8(11 - 3) - 2(4 + 1)

11 - 3 = 8

4 + 1 = 5

8(5) - 2(5)

8 * 5 = 64

2 * 5 = 10

64 - 10 = 54

8 0

4 years ago

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12<2x+2≤22 plz help me tnx

Alja [10]

Firstly, subtract 2 from all sides of this inequality: $10$

Next, divide by 2 on all sides of the inequality and <u>your answer will be $5$ </u>

7 0

3 years ago

The infinite geometric sum formula can be used to write 0.126126126...as a fraction. What is the numerator of this reduced fract

Allisa [31]

Answer:

B.14

Step-by-step explanation:

0.126126126... = x

1000x = 126.126126...
1000x - x = 126
999x = 126
x = 126/999= 42/333= 14/ 111

Numerator is 14

Correct answer is B.14

8 0

3 years ago

Let c be the path c(t) = (2t, t2, log(t)), defined for t > 0. find the arc length of c between the points (2, 1, 0) and (12,

V125BC [204]

The path starts at $t=1$ and ends at $t=6$ , so we have an arc length of

$\displaystyle\int_{\mathcal C}\mathrm dS=\int_{t=1}^{t=6}\|\mathbf c'(t)\|\,\mathrm dt$
$=\displaystyle\int_1^6\sqrt{2^2+(2t)^2+\left(\frac1t\right)^2}\,\mathrm dt$
$=\displaystyle\int_1^6\sqrt{4t^2+4+\frac1{t^2}}\,\mathrm dt$
$=\displaystyle\int_1^6\frac1t\sqrt{4t^4+4t^2+1}\,\mathrm dt$
$=\displaystyle\int_1^6\frac1t\sqrt{(2t^2+1)^2}\,\mathrm dt$
$=\displaystyle\int_1^6\frac{2t^2+1}t\,\mathrm dt$
$=\displaystyle\int_1^6\left(2t+\frac1t\right)\,\mathrm dt$
$=t^2+\log t\bigg|_{t=1}^{t=6}$
$=(6^2+\log6)-(1^2+\log1)=35+\log6$

4 0

4 years ago

How many solutions does this system of equations have? Use either the substitution method or the elimination method. −2x + 4y =

timama [110]

No solution

-2x+4y=4
2(x-2y=6)

-2x+4y=4
2x-4y =12
0=16

4 0

3 years ago

Read 2 more answers