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damaskus [11]
2 years ago
7

Can someone please help me with both these questions? You will get 20pts

Mathematics
1 answer:
Volgvan2 years ago
3 0

Answer:

#1) -3 feet

#2) 5hours

Step-by-step explanation:

#1) you need to find the rate of change- feet per minute

To find the rate, divide -12 feet by 4 minutes (the twelve in negative because it decreases, almost like subtraction)

-12/4= -3 feet per minute.

Now, multiply by amount of minutes- -3x1=  -3 feet in 1 minute

#2) To find the maount of degrees each hour,

divide 10 degrees by 2 degrees per hour.

10/2=5 hours

Hope this helps :)- please give me brainliest!!

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The length of ZX is 2 units. What is the perimeter of triangle XYZ?
dezoksy [38]

Keywords

triangle,perimeter,distance, length, side, points

we know that

The <u>perimeter</u> of a<u> triangle</u> is the sum of the three <u>length</u> <u>side</u>

To find the<u> length</u> <u>side</u> calculate the <u>distance</u> between two <u>points</u>

The formula to calculate the <u>distance</u> between to <u>points</u> is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}


Step 1

Find the <u>distance</u> ZY

Z(1,0)\\Y(3,1)  

substitute the values


d=\sqrt{(1-0)^{2}+(3-1)^{2}}


dZY=\sqrt{5}\ units


Step 2

Find the <u>distance</u> XY

X(-1,4)\\Y(3,1)  

substitute the values


d=\sqrt{(1-4)^{2}+(3+1)^{2}}


dXY=\sqrt{25}=5\ units  

Step 3

Find the <u>perimeter</u> of the <u>triangle</u>

P=ZX+ZY+XY

we have

dZX=2\sqrt{5}\ units


dZY=\sqrt{5}\ units


dXY=5\ units  

Substitute

P=(2\sqrt{5}+\sqrt{5}+5)\ units

therefore

the answer is

P=(3\sqrt{5}+5)\ units

4 0
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The first one includes both
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$300 at 4% for 3 years. what is th interest of money? and what is the balance of the amount
Norma-Jean [14]

Answer:

$36.00

Step-by-step explanation:


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What is the equivalent radian measure of 600?​
pychu [463]

Answer:

=  \frac{ \theta}{180}  \times \pi \\  =  \frac{600}{180}  \times \pi \\  =  \frac{10}{3} \pi

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3 years ago
A converging lens of focal length 5 cm is placed at a distance of 20
lesya [120]

The object should be placed 20/cm from the lens so as to form its real image on the screen

<h3>Mirror equation</h3>

The mirror equation is given according to the expression below;

1/f = 1/u + 1/v

where

f is the focal length

u is the object distance

v is the image distance

Given the following parameters

f = 5cm

v = 20cm

Required

object distance u

Substitute

1/5 = 1/u +1/20

1/u = 1/5-1/20
1/u = 3/20

u = 20/3 cm

Hence the object should be placed 20/cm from the lens so as to form its real image on the screen

Learn more on mirror equation here; brainly.com/question/27924393

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