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3 years ago

PLEASE ANSWER BOTH OF THESE QUESTIONS HONESTLY, IM GIVING OUT BRAINLIEST AND 50 POINTS TO WHOEVER GETS THEM BOTH CORRECT! :D

Mathematics

2 answers:

Sloan [31]3 years ago

8 0

Answer:

D, A

Step-by-step explanation:

Graphed them and they matched up to your graphs

y= 2/3x

y=4/3x-5

SVEN [57.7K]3 years ago

6 0

Answer:

1st graph: D) Y = 2/3x

2nd graph: A) Y = 4/3x - 5

Step-by-step explanation:

Hope this helps. Pls give brainliest!

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Could anyone help me on number 3?

xeze [42]

Answer:

n = 2m-4

Step-by-step explanation:

n+2/m-1=2

n+2=2(m-1)

n+2=2m-2

n=2m-2-2

n=2m-4

6 0

3 years ago

One cubic meter of water weighs approximately 2200 pounds. There are 100 cm in one meter. If you have a box-shaped fish tank tha

Diano4ka-milaya [45]

Answer:

158.4 pounds

Step-by-step explanation:

first find the volume of the tank

$V = 30 \times 30 \times 80$

$V = 72000 cm^3$

to convert this to m^3 we know that 1m = 100cm

$V = 72000 cm^3 \times \left(\dfrac{1\,\text{m}}{100\,\text{cm}}\right)^3$

$V = 72000 cm^3 \times \left(\dfrac{1\,\text{m}^3}{100^3\,\text{cm}^3}\right)$

the cm^3 cancel out.

$V = \dfrac{72000}{100^3} m^3$

$V = 0.072\,m^3$

by simply converting the side-lengths to meters beforehand can give you this answer directly:

$V = 0.3 \times 0.3 \times 0.8 = 0.072 m^3$

it is given that 1 meter cube of water weighs about 2200 pounds.

$1\,m^3 = 2200 \,\text{lb}$

multiply both sides with 0.072 to find our answer:

$1\,m^3 \times 0.072 = 2200 \times 0.072 \,\text{lb}$

$0.072\,m^3 = 158.4 \,\text{lb}$

hence the weight of the water in the tank would be 158.4 pounds!

3 0

3 years ago

Are y = 1/4 -2 and y = 1/4 + 2 parallel?

zhenek [66]

Answer:

yes because the slope is equal. so these two lines are parallel.

3 0

3 years ago

If the endpoints of AB have the coordinates A(9, 8) and B(-1, -2), what is the midpoint of AB?

pickupchik [31]

The midpoint, if the endpoints are (x₁,y₁) and (x₂,y₂):
$(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

$(9,8) \\
x_1=9 \\ y_1=8 \\ \\
(-1,-2) \\
x_2=-1 \\ y_2=-2 \\ \\
\frac{x_1+x_2}{2}=\frac{9-1}{2}=\frac{8}{2}=4 \\
\frac{y_1+y_2}{2}=\frac{8-2}{2}=\frac{6}{2}=3$

The midpoint of AB is (4,3).

5 0

3 years ago

Read 2 more answers

Write the equation of a line in slope-intercept form with a slope of -1/3 and a y intercept of 4

Sergeu [11.5K]

Y = -1/3x + 4 . 4 is the intercept -1/3x is the slope

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3 years ago