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3 years ago

10

May someone please help me with number 18 and 19?

1 answer:

scoray [572]3 years ago

6 0

For number 18 you would first want to convert all the measurements so you can determine who walked the furthest.....In this case we will convert the feet's and inches to yards because yards are longer..

Janelle - 429ft. 8in = about 143 yards
Lydia- 460 ft = about 153 yards

in this case I believe Lydia walked the farthest...

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There are two pizzas. Conor ate 1⁄4 of a pizza, Brandon 2⁄8, Tyler 3⁄4, and Audrey 4⁄8. Who ate the most of the two pizzas?

Semenov [28]

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3 years ago

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V125BC [204]

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Step-by-step explanation:

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3 years ago

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Which is a rational number <br>a) 1.4142135623<br>b) 3.6256256<br>c) 2 (pie)<br>d) squared 5

vfiekz [6]

Answer:

Rational numbers can be expressed as a fraction

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2 years ago

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allowing 20% discount on the marked price of a watch the value of the watch will be Rs 6328 when a vat 13%is added ,find the fin

Ahat [919]

Step-by-step explanation:

Let the marked price of a watch be =₹x

∴ Discount price = x- 20% of x

= x - 0.2x

=0.8x

Amount of VAT = 13% of 0.8x

0.13 x 0.8x

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2 years ago

Which table represents the graph of a logarithmic function in the form y=log3x when b>1?

alex41 [277]

Answer:

<u><em>The satisfied table of the given function</em></u> $y = log_{b} (x)$ <u><em></em></u>

<em>x 1/8 1/4 1/2 1 2</em>

<em>y -3 -2 -1 0 1</em>

<em></em>

Step-by-step explanation:

<u><em>Explanation</em></u> :-

Given logarithmic function $y = log_{b} (x)$ if b >1

Given first table

i)

put x = $\frac{1}{8}$ given b > 1 so we can choose b = 2

$y = log_{2} (\frac{1}{8} )$

$y = log_{2} (2^{-3} )$

we will apply logarithmic formula

log x ⁿ = n log (x)

$y = log_{2} (2^{-3} ) = -3 log_{2} (2) = -3 (1) = -3$

<em>y = -3</em>

<em>ii)</em>

<em>put x = </em> $\frac{1}{4}$ <em> given b > 1 so we can choose b = 2</em>

<em></em> $y = log_{2} (\frac{1}{4} )$ <em></em>

<em></em> $y = log_{2} (2^{-2} )$ <em></em>

we will apply logarithmic formula

log x ⁿ = n log (x)

$y = log_{2} (2^{-2} ) = -2 log_{2} (2) = -2 (1) = -2$

<em>y = -2</em>

<em>iii) </em>

<em>put x = </em> $\frac{1}{2}$ <em> given b > 1 so we can choose b = 2</em>

<em></em> $y = log_{2} (\frac{1}{2} )$ <em></em>

$y = log_{2} (2^{-1} )$

<em>we will apply logarithmic formula </em>

<em>log x ⁿ = n log (x)</em>

$y = log_{2} (2^{-1} ) = -1 log_{2} (2) = - (1) = -1$

<em>y = -1</em>

<em>iv) </em>

<em>put x = 1 given b > 1 so we can choose b = 2</em>

<em></em> $y = log_{2} (1 )$ <em> = 0</em>

<em>y = 0</em>

<em>v) </em>

<em>put x = </em> $2$ <em> given b > 1 so we can choose b = 2</em>

$y = log_{2} (2 )$

<em>y = 1</em>

<em></em>

<u><em>Final answer:-</em></u>

<u><em>The satisfied table of the given function</em></u>

<em>x 1/8 1/4 1/2 1 2</em>

<em>y -3 -2 -1 0 1</em>

<em></em>

8 0

3 years ago

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