May someone please help me with number 18 and 19?
1 answer:
You might be interested in
A 33 gram sample has k value of .1124
(Actually I think the problem SHOULD be worded: A 33 gram sample has k value of -.1124/days)
See attached graphic:
Half-Life = ln (.5) / k
Half-Life = -.693147 / -.1124/days
Half-Life = <span> <span> <span> 6.1667882562 </span> </span> </span> days
Source:
http://www.1728.org/halflif2.htm
(Actually I think the problem SHOULD be worded: A 33 gram sample has k value of -.1124/days)
See attached graphic:
Half-Life = ln (.5) / k
Half-Life = -.693147 / -.1124/days
Half-Life = <span> <span> <span> 6.1667882562 </span> </span> </span> days
Source:
http://www.1728.org/halflif2.htm
First, apply this following rule:
Second, apply this following rule:
Third, multiply 1 × 6 to get 6 and 6 × 2 to get 12.
Fourth, find the GCF of 6 and 12.
Factors of 6: 1, 2, 3, 6
Factors of 12: 1, 2, 3, 4, 6, 12
The GCF is 6.
Fifth, divide the numerator by the GCF.
Sixth, divide the denominator by the GCF.
Seventh, collect the new numerator and new denominator.
Answer as fraction:
Answer as decimal: 0.5