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Vesnalui [34]
2 years ago
10

The set of ordered pairs represents a function

Mathematics
1 answer:
Snezhnost [94]2 years ago
5 0

Answer:

12

Step-by-step explanation:

because it digit havbeen given ad k

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What is 10 to the 8th power multiplied by 30 subtract 3
IceJOKER [234]

Answer:

21

Step-by-step explanation:

4 0
2 years ago
Write the radical below in the simplest radical form<br><br> √210 <br><br> Pls show ur work
Anna [14]

Answer:

\sqrt{210}

Step-by-step explanation:

Let's look at the prime factors of 210.

210 = 2 * 3 * 5 * 7

\sqrt{210} = \sqrt{2 \times 3 \times 5 \times 7} = \sqrt{210}

Since no factor appears more than once, this radical cannot be simplified.

3 0
2 years ago
What are the solutions to the equation? use the quadratic formula to solve the equation. 2y²-10y+8=0
Ludmilka [50]
The answer is D for this one
4 0
3 years ago
I need help please! ​
Sophie [7]

Answer/Step-by-step explanation:

Area of trapezium = ½*(AD + BC)*AB

Area = 42 cm²

AD = (x + 8) cm

BC = (x + 5) cm

AB = x cm

Plug in the values into the equation

42 = ½((x + 8) + (x + 5))*x

42 = ½((x + 8 + x + 5)*x

42 = ½(2x + 13)*x

Multiply both sides by 2

42*2 = (2x + 13)*x

84 = 2x² + 13x

2x² + 13x = 84

Subtract both sides by 84

2x² + 13x - 84 = 0

4 0
2 years ago
25 POINTS
uysha [10]

Answer:

a reflection over the x-axis and then a 90 degree clockwise rotation about the origin

Step-by-step explanation:

Lets suppose triangle JKL has the vertices on the points as follows:

J: (-1,0)

K: (0,0)

L: (0,1)

This gives us a triangle in the second quadrant with the 90 degrees corner on the origin. It says that this is then transformed by performing a 90 degree clockwise rotation about the origin and then a reflection over the y-axis. If we rotate it 90 degrees clockwise we end up with:

J: (0,1) , K: (0,0), L: (1,0)

Then we reflect it across the y-axis and get:

J: (0,1), K:(0,0), L: (-1,0)


Now we go through each answer and look for the one that ends up in the second quadrant;

If we do a reflection over the y-axis and then a 90 degree clockwise rotation about the origin we end up in the fourth quadrant.

If we do a reflection over the x-axis and then a 90 degree counterclockwise rotation about the origin we also end up in the fourth quadrant.

If we do a reflection over the x-axis and then a reflection over the y-axis we also end up in the fourth quadrant.

The third answer is the only one that yields a transformation which leads back to the original position.

4 0
3 years ago
Read 2 more answers
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