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jok3333 [9.3K]
3 years ago
10

Given a function f(x)=2x^2+3, what is the average rate of change of f on the interval [2, 2+h]?

Mathematics
1 answer:
-Dominant- [34]3 years ago
3 0
-8h - 2h^2

f(2)-f(2+h) = -8h - 2h^2


Mark brainliest please
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Lee and two friends shared a pizza. She also bought a lemonade for $2.25. Lee's share of the bill was $7.25.What was the total c
GaryK [48]

Answer:

$15

Step-by-step explanation:

You first need to subtract 2.25 from 7.25 which leaves you with 5 dollars. Since Lee's share of the pizza cost 5 dollars, and 3 people ate the pizza, you need to multiply 5*3 and get 15 dollars. This is the total pizza cost.

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How many 90 degrees angles does it take to make a full turn
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Four because 90+90+90+90 = 360, which is the angle f a circle 
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A TV that usually sells for $195.72 is on sale for 20% off. If sales tax on the TV is 9%, what is the price of the TV, including
Nuetrik [128]

The total cost of the TV is: $181.57


Work: 195.72 x 0.20 (20%) = 39.14

195.72 - 39.14 = 166.58 <-- Was for the discount now you have to do the tax.


Now Tax, 166.58 + 14.99 = 181.57


Hope this helps!

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3 years ago
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How many solutions does the equation 6x-10=2(3x+8) have?
ivanzaharov [21]

Answer:

No solution

Step-by-step explanation:

As 6x on lhs and 2×3x on the rhs are equal and cancel each other

6 0
3 years ago
Two children own two-way radios that have a maximum range of 3 miles. One leaves a certain point at 1:00 P.M., walking due north
Grace [21]

Answer:

The answer is 21 minutes

Step-by-step explanation:

We use the equation Xf = Xo + vt

1) At 1:00 PM, child one leaves the starting point heading north at a constant velocity of 6 mi/hr or .1 [mi/min] (divide by 60 to convert from [mi/hr] to [mi/min])

2) He walks for 15 minutes before kid 2 starts walking. In 15 minutes he is able to cover 1.5 [mi]

  • x_{1f1} =x_{o} +v_{1} t_{1} \\x_{1f1} =0+.1(15)\\x_{1f1} =1.5 [mi]

3) Now, child 2 starts walking and we know that when the range reaches 3 miles, they won´t be able to communicate. So the sum of the final position of child 1 and child 2 must be 3[mi]

  • Child 1 final position => x_{1f} = x_{1f1} +v_{1} t\\x_{1f} =1.5+v_{1} t
  • Child 2 final position => x_{2f} =0+v_{2} t

4) Sum the equations and equate to 3

  • x_{1f} +x_{2f} =3

5) Substitute the values we already know

  • 1.5+v_{1} t+v_{2}t=3\\ 1.5+.1t+.15t=3\\1.5+.25t=3\\t=\frac{3-1.5}{.25} \\t=6 [min]

6) in 15 + 6 minutes they will be 3miles apart

7) In 21 minutes they will still be able to communicate with one another.

7 0
3 years ago
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