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algol [13]
3 years ago
5

Help ASAP brainliest

Mathematics
1 answer:
Zepler [3.9K]3 years ago
6 0

Answer:

you are correct

because when you add and calculate All the answers you will know it is correct

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Lina20 [59]

Answer:

All you have to do- if you are on a computer- take a screenshot and then go to the paperclip button and select the file.

Step-by-step explanation:

Hope this helps :)

8 0
3 years ago
Larry has 9 yards of fabric. He will use 2 yards to make each vest. How many vests
elena-14-01-66 [18.8K]

Answer:

4 vests

Step-by-step explanation:

Larry has 9 yards of fabric, in which 2 are needed to make a vest.

Divide 9 with 2: 9/2 = 4.5

However, note that you cannot have half a vest, so you must round down.

4.5 becomes 4.

4 vests is the maximum Larry can make with 9 yards of fabric.

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8 0
3 years ago
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Solve. 4+ x/7 = 2. plss...​
galina1969 [7]

Answer:

-21

Step-by-step explanation:

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8 0
3 years ago
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Find the exact values of a) sec of theta b)tan of theta if cos of theta= -4/5 and sin<0
Gre4nikov [31]

Answer:

Using trigonometric ratio:

\sec \theta = \frac{1}{\cos \theta}

\tan \theta = \frac{\sin \theta}{\cos \theta}

From the given statement:

\cos \theta = -\frac{4}{5} and sin < 0

⇒\theta lies in the 3rd quadrant.

then;

\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}

Using trigonometry identities:

\sin \theta = \pm \sqrt{1-\cos^2 \theta}

Substitute the given values we have;

\sin \theta = \pm\sqrt{1-(\frac{-4}{5})^2 } =\pm\sqrt{1-\frac{16}{25}} =\pm\sqrt{\frac{25-16}{25}} =\pm \sqrt{\frac{9}{25} } = \pm\frac{3}{5}

Since, sin < 0

⇒\sin \theta = -\frac{3}{5}

now, find \tan \theta:

\tan \theta = \frac{\sin \theta}{\cos \theta}

Substitute the given values we have;

\tan \theta = \frac{-\frac{3}{5} }{-\frac{4}{5} } = \frac{3}{5}\times \frac{5}{4} = \frac{3}{4}

Therefore, the exact value of:

(a)

\sec \theta =-\frac{5}{4}

(b)

\tan \theta= \frac{3}{4}

7 0
4 years ago
PLSSS SOMEONE HELP ME ILL GIVE U BRAINLIEST
Maksim231197 [3]

Answer:

(0,d)

Step-by-step explanation:

4 0
3 years ago
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