Question

PLEASEE HELP

Answer 1

Considering that angles A and C are equal, and the sum of the internal angles of a triangle is 180º, we have that:

The measure of angle A is of: 48º.

The measure of angle B is of: 84º.

The measure of angle C is of: 48º.

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• Segments AC and CB have the same length, thus, angles A and C have the same measure, and then:

$6(x - 3) = 4(x + 1)$

$6x - 18 = 4x + 4$

$2x = 22$

$x = \frac{22}{2}$

$x = 11$

$6(11 - 3) = 6(8) = 48$

The measure of angle A is of: 48º.

The measure of angle C is of: 48º.

The sum of the internal angles of a triangle is of 180º, and this is used to find the measure of angle B.

$mA + mB + mC = 180$

$2(48) + mB = 180$

$mB = 84$

The measure of angle B is of: 84º.

A similar problem is given at brainly.com/question/13216436