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2 years ago

If you have a number by using multiplication and it gives you 13

Mathematics

2 answers:

Stolb23 [73]2 years ago

3 0

The answer is 7.21...

Degger [83]2 years ago

3 0

The answer is 7.21. hope this helps

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Use the cumulative normal distribution table to find the z-scores thqt bound the middle of 68% of theje area under the stanrard

padilas [110]

Answer:

Z scores between -0.995 and 0.995 bound the middle 68% of the area under the stanrard normal curve

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Middle 68%

Between the 50 - (68/2) = 16th percentile and the 50 + (68/2) = 84th percentile.

16th percentile:

X when Z has a pvalue of 0.16. So X when Z = -0.995

84th percentile:

X when Z has a pvalue of 0.84. So X when Z = 0.995.

Z scores between -0.995 and 0.995 bound the middle 68% of the area under the stanrard normal curve

7 0

3 years ago

Leno4ka [110]

Answer:

$\frac{s^2-25}{(s^2+25)^2}$

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given: $\mathcal{L}[t \cos 5t]=(-1)F'(s)$ with $F(s)=\mathcal{L}[\cos 5t]$ .

Now, $F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt$ . Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that $F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt$ .

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

$F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s)$ .

Solving for F(s) on the last equation, $F(s)=\frac{s}{s^2+25}$ , then the Laplace transform we were searching is $-F'(s)=\frac{s^2-25}{(s^2+25)^2}$

3 0

3 years ago

I need help on this question

schepotkina [342]

Answer:

0 4 9 1

_____________

1 9 9 3 2 9

− 0

9 3

− 7 6

1 7 2

− 1 7 1

1 9

− 1 9

Step-by-step explanation:

Sorry of this isn't clear

6 0

3 years ago

In the scale used on a blueprint 1/4 inch represent 3 feet on the blueprint what is the length of the room with an excellent of

BigorU [14]

You would do 24 times 3 and get 72 or divide 24 by 1/4=0.25

3 0

2 years ago

Which expression is equivalent to 4x + ? o 1(-x+2) o 1(-2+ 3) -1(-x+ ) - (x + 2)

slavikrds [6]

Answer:

Definitely Option A.

When you expand the bracket of Option A... You have your equation

Which is

-1/4x + 1/2.

7 0

3 years ago