2 years ago

Write a conjecture about each value or geometric relationship. A(-1,-1) B(2,2) C(4,4)

Mathematics

1 answer:

Mama L [17]2 years ago

5 0

Answer:

4. A(-1, -1), B(2, 2), C(4, 4). 5. ∠1 and ∠2 form a right angle.

Step-by-step explanation:

You might be interested in

identify the graph of 9x^2-25y^2=225 for t(0 5) and write an equation of the translated or rotated graph in general form

tamaranim1 [39]

ANSWER

The required equation is:

$9 {x}^{2} - 25{y}^{2} + 250y - 85 0=0$

EXPLANATION

The given equation is

$9 {x}^{2} - 25 {y}^{2} = 225$

Dividing through by 225 we obtain;

$\frac{ {x}^{2} }{25} - \frac{ {y}^{2} }{9} = 1$

This is a hyperbola that has it's centre at the origin.

If this hyperbola is translated so that its center is now at (0,5).

Then its equation becomes:

$\frac{ {(x - 0)}^{2} }{25} - \frac{ {(y - 5)}^{2} }{9} = 1$

We multiply through by 225 to get;

$9 {x}^{2} - 25( {y - 5})^{2} = 225$

We now expand to get;

$9 {x}^{2} - 25( {y}^{2} - 10y + 25 )= 225$

$9 {x}^{2} - 25{y}^{2} + 250y - 6 25 = 225$

The equation of the hyperbola in general form is

$9 {x}^{2} - 25{y}^{2} + 250y - 85 0=0$

5 0

3 years ago

Read 2 more answers

jolli1 [7]

Answer:

Acceleration equals zero because of constant velocity

$f - fr = ma \\ 70 \cos(30) - fr = 0 \\ 70 \cos(30) = fr \\ fr \: = 60.62$

coefficient

Fr = coefficient × r

60.62= ce ×100

0.60 = coefficient

6 0

3 years ago

Factor 6y^2(y^2+6y+9) completely.

natali 33 [55]

$6y^2(y^2+6y+9)\\\\=6y^2(y^2+2\cdot 3 \cdot y + 3^2)\\\\=6y^2(y+3)^2\\\\=6y^2(y+3)(y+3)$

7 0

2 years ago

Which is the value of the rational expression 6-x/x+5 when x=2

Allisa [31]

Answer:

4/7

Step-by-step explanation:

6-x/x+5 let us take x=2

6-2/2+5=4/7

8 0

3 years ago

92 divided by 4 use partial and quotients to divide

kherson [118]

The partial quotient is 23

8 0

3 years ago

Read 2 more answers