If C is the midpoint of BD and AE,then AB should be congruent to DE due to the midpoint property. If 2 segments have the same midpoints,then the segments have to be congruent to each other
Answer:
1041
Step-by-step explanation:
Among the numbers 1–1000, there are 31 squares, so the sequence will extend to at least 1031. In those added numbers, there is another square (1024), so the sequence must extend to at least 1032.
There are 7 more numbers that are cubes, but not squares, so the sequence must extend to at least 1039.
And there are 2 additional numbers that are 5th powers that are not squares or cubes. Compensating for the removal of these numbers extends the end of the sequence to 1041.
There are no numbers in this range that are both cubes and 5th powers and that have not already been accounted for. (The only 15th power is 1.)
Hence, the 1000th number in the sequence is 1041.
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This result is verified by a computer program that listed the numbers.
Answer:
Where is the question or figure ???
Answer:
figure 3
Step-by-step explanation:
see attached
x coordinates is the nuts
and y coordinates is the raisings
