**Answer:**

The system of linear inequalities represented by the graph is:

y > (2/3) x + 3 and y <= - (1/3) x + 2

**Step-by-step explanation:**

In the graph we can see the region on and below the red line, and above the black dashed line.

1) The red line goes through the points:

P1=(0,2)=(x1,y1)→x1=0, y1=2

P2=(3,1)=(x2,y2)→x2=3, y2=1

The slope of this line is:

s=(y2-y1)/(x2-x1)

Replacing the known values:

s=(1-2)/(3-0)

s=(-1)/(3)

s=-(1/3)

The equation of the red line is:

y-y1=s(x-x1)

y-2=-(1/3)(x-0)

y-2=-(1/3)x

y-2+2=-(1/3)x+2

y=-(1/3)x+2

The area on and below the red line is: y<=-(1/3)x+2

2) The black dashed line goes through the points:

P1=(-3,1)=(x1,y1)→x1=-3, y1=1

P2=(0,3)=(x2,y2)→x2=0, y2=3

The slope of this line is:

s=(y2-y1)/(x2-x1)

Replacing the known values:

s=(3-1)/(0-(-3))

s=(2)/(0+3)

s=(2)/(3)

s=(2/3)

The equation of the red line is:

y-y2=s(x-x2)

y-3=(2/3)(x-0)

y-3=(2/3)x

y-3+3=(2/3)x+3

y=(2/3)x+3

The area above the black dashed line is: y>(2/3)x+3

Then, the system of linear inequalities represented by the graph is:

y>(2/3)x+3 and y<=-(1/3)x+2