Both lines are parallel so using the bottom line you are given angle 7 as being 80 degrees. Angle 5 and 7 form a straight line which is 180 degrees so angle 5 would be 180-80 = 100 degrees.
Angle 1 is the same as angle 5 so angle 1 is 100 degrees.
Answer: 100 degrees
X + y = 180
Y = wheat, x = oats
Y = x + 20. In the 1st equation, get y by itself getting y = 180 - x.
So 180 - x = x + 20. Subtract x on both sides to get 180 - 2x is 20. Subtract 180 to both sides is -2x = -160. Divide -2 to both sides is x = 80. So 80 + 20 is 100 wheat, and 80 oats of acres.
F(t)
= t2 + 4t − 14
y + 14 + 4 = (
t2 + 4t +4)
y + 18 = ( t +
2)^2
so the vertex
of the parabola is ( -2 , -18)
<span>the axis of
symmetry is y = -18</span>
<h2>Question #22 Answer</h2>
B. 2 in.
<h3>Explanation:</h3>
Cross out the common factor
________________________________________________________
<h2>Question #23 Answer (Picture attached)</h2>
D. proportional, equal
<h3>Explanation:</h3>
Δ
Δ × 
Answer:
Demand is Elastic when Price > 200 ; Demand is inelastic when Price < 200
Step-by-step explanation:
p = 400 - 4x
4x = 400 - p
x = (400 - p) / 4 → x = 100 - p/4
Elasticity of demand [ P ed ] = (Δx / Δp) x (p / x)
Δx / Δp [Differentiating x w.r.t p] = 0 - 1/4 → = -1/4
P ed = <u>-1</u> x<u> p </u>
4 (400 - p)/4
= <u>-1</u> x <u> 4p </u> = -p / (400-p)
4 (400 - p)
Price Elasticity of demand : only magnitude is considered, negative sign is ignored (due to negative price demand relationship as per law of demand).
So, Ped = p / (400 - p)
Demand is Elastic when P.ed > 1
p / (400-p) > 1
p > 400 - p
p + p > 400 → 2p > 400
p > 400 / 2 → p > 200
Demand is inelastic when P.ed < 1
p / (400-p) < 1
p < 400 - p
p + p < 400 → 2p < 400
p < 400 / 2 → p < 200
