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Zanzabum
2 years ago
10

-14=-20y-7x 10y+4=2x Solve by Elimination please!

Mathematics
1 answer:
iogann1982 [59]2 years ago
8 0

Answer:

x = 2    y = 0

Step-by-step explanation:

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5 0
3 years ago
The price of a video game was reduced from $70.00 to $40.00. By what percentage was the price of the
Sauron [17]

Answer:

43%

Step-by-step explanation:

(40-70) ÷ 70 = -30 ÷ 70 = -0.43 or -43%

Answer: The video game was reduced by 43%.

3 0
3 years ago
Someone please help me answer this!!
Liula [17]

Answer:

100 in is the answer.

Step-by-step explanation:

a = 60 in

b = 80 in

c = ?

According to the Pythagorean theorem,

a² + b² = c²

60² + 80² = c²

3600 + 6400 = c²

c² = 10000

c = 100 in

∴ the distance between the opposite corners of the bed is 100 in

7 0
2 years ago
A family has two cars. The first car has a fuel efficuency of 15 miles per gallon of gas and the second has a fuel efficiency of
SVEN [57.7K]

Answer:

x= 35 gallons consumed by 1st car

and y= 40  gallons consumed by 2nd car

Step-by-step explanation:

Fuel efficiency of 1st car = 15 miles per gallon

Fuel efficiency of 2nd car = 35 miles per gallon

Let x= gallons consumed by 1st car

and y= gallons consumed by 2nd car

Total gallons consumed by both cars = 75

so, we can write

x + y = 75

Miles covered by both cars = 1925 miles

and we know, Fuel efficiency of 1st car = 15 miles per gallon

Fuel efficiency of 2nd car = 35 miles per gallon

we can write the equation as

15 x + 35 y = 1925

where x and y are gallons consumed by 1st and 2nd car.

We have two equation now,

x + y = 75                   (1)

15 x + 35 y = 1925     (2)

Multiplying eq(1) with 15 and subtracting eq (1) and 2

15 x + 15 y = 1125

15 x + 35 y = 1925

-       -            -

_______________

0 - 20 y = -800

y= -800 / -20

y = 40

Putting value of y in equation 1

x + y = 75

x + 40 = 75

x= 75 - 40

x = 35

x= 35 gallons consumed by 1st car

and y= 40  gallons consumed by 2nd car

4 0
3 years ago
HELLPP!!!!!!!!!!!!!!!!!!!!!!!!!
Genrish500 [490]

\left\{\begin{array}{ccc}2x-3y=-27&|\cdot3\\-3x+2y=23&|\cdot2\end{array}\right\\\underline{\left\{\begin{array}{ccc}6x-9y=-81\\-6x+4y=46\end{array}\right}\ \ \ \ |\text{add both sides}\\.\ \ \ \ \ \ -5y=-35\ \ \ \ \ |:(-5)\\.\ \ \ \ \ \ \ \ y=7\\\\\text{put the value of y to the first equation}\\\\2x-3(7)=-27\\\\2x-21=-27\ \ \ \ |+21\\\\2x=-6\ \ \ \ |:2\\\\x=-3\\\\\text{Answer:}\ x=-3,\ y=7\to\boxed{(-3,\ 7)}

6 0
3 years ago
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