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ale4655 [162]
3 years ago
13

Which is greater? A. 3 1/2 or B. 3 1/8

Mathematics
2 answers:
OleMash [197]3 years ago
8 0

Answer:

3 1/2 = 7/2

3 1/8 = 25/8

7/2 x 4 = 28/8

7/2 (3 1/2) < 25/8 (3 1/8)

Therefore, 3 1/8 is greater than 3 1/2

Step-by-step explanation:

sukhopar [10]3 years ago
8 0

Answer:

A it is 3 1/2

Step-by-step explanation: that is a larger amount so it is greater

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A news service conducted a survey of 1077 adults ages 18 years or older in a certain​ country, August 31−September ​2, 2015. The
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Answer:

To determine the percent of adults in the country who believe that the federal government wastes 51 cents or more of every dollar.

Step-by-step explanation:

As per the given scenario, the research objective is :

To determine the percent of adults in the country who believe that the federal government wastes 51 cents or more of every dollar from the population that contains, adults of the country who are aged 18 years or older.

7 0
4 years ago
Read 2 more answers
Find the value of x.
elena-s [515]
Hi there!

Using the formula - n-2*180 -, we know that the interior angles of a pentagon add up to 540. We can use the values we're given and add them together and set them all equal to 540, then solve.

WORK:
540 = 204 + 12x 
336 = 12x
x = 28

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
8 0
4 years ago
In ΔABC, m∠ACB = 90°, CD ⊥ AB and m∠ACD = 45°. Find: CD, if BC = 3 in
IRISSAK [1]
We can find m∠BCD like follows: m∠BCD=90°-45°=45<span>°
Now, m</span><span>∠DBC= 180°-(90°+45°)=45°

Remember that </span>sin \alpha = \frac{opposite leg}{hypotenuse}, so oppositeleg=(hypotenuse)(sin \alpha )

We know that hypotenuse= BC= 3in and \alpha=∠DBC)=45°, so replacing the values we get:
CD=3sin(45)=2.12

We can conclude that the segment CD is 2.12 in
4 0
3 years ago
Read 2 more answers
Hansika paid $9.25 for 2.8 pounds of pretzels. About how much did she pay for a pound of pretzels?
NeX [460]
Answer: $3.30

Explanation: 
You set up a proportion where 

9.25      X
------ = -----
2.8        1

Then you cross multiply and see that...
2.8X = 9.25
Then X = 9.25 / 2.8 = 3.30

4 0
3 years ago
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3.30 Survey response rate. Pew Research reported in 2012 that the typical response rate to their surveys is only 9%. If for a pa
Artist 52 [7]

Answer:

0% probability that at least 1,500 will agree to respond

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 15000, p = 0.09

So

\mu = E(X) = np = 15000*0.09 = 1350

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{15000*0.09*0.91} = 35.05

What is the probability that at least 1,500 will agree to respond

This is 1 subtracted by the pvalue of Z when X = 1500-1 = 1499. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1499 - 1350}{35.05}

Z = 4.25

Z = 4.25 has a pvalue of 1.

1 - 1 = 0

0% probability that at least 1,500 will agree to respond

6 0
4 years ago
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