Notice the picture below
the lateral area, or just the area of the sides, well, the sides are really just 4 triangles, so just get the area of each, and sum them up, that's the lateral area
Since ABCD is a parallelogram, line AB and line DC are parallel and has the same value.
To solve this, equate line AB to be equal with line DC.
So,
Line AB = Line DC
(9x-14)in = (3x +4)in
Next group like terms to get the value of x
9x in-3x in = 4in+14in
=
x = 3in
Since, we now have the value of x, substitute it to line DC’s equation.
DC=(3x+4)in
DC=(3(3) +4)in
DC=(9 +4) in
DC= 13 in
To check if the value is really correct, substitute X to AB
AB=(9x -14)in
AB=(9(3)-14)in
AB=(27-14)in
AB=13 in
Yes the equations are equivalent
So for number 2 i am 100% on which the area of the triangle is 6.
and then 1 i think not 100% sure is an acute angle again not 100%
then 3. it don't make sense to me so idk about that 1 srry.
~Good Luck~
I will show you the steps on how you get that answer and if you have any questions after that let me know and I'd be more than happy to help answer them for you.
The first step for solving (1 + y)² is to use the equation (a + b)² = a² + 2ab + b² to expand the expression.
1² + 2 × 1y + y²
1 raised to any power equals 1,, so remove the power.
1 + 2 × 1y + y²
Calculate the product of 2 × 1y.
1 + 2y + y²
Finally,, use the commutative property to reorder the terms.
y² + 2y + 1
Let me know if you have any further questions.
:)
