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3 years ago

Suppose that 18 inches of wire costs 72 cents.

Mathematics

1 answer:

NeX [460]3 years ago

7 0

Answer:

41 inches of wire will cost 164 cents.

Step-by-step explanation:

1st Method

Use proportions!

18/ 72 = 41/ c

Cross multiply

18 * c = 72 * 41

18c = 2952 divide both sides by 18

<em>c = 164</em>

2nd Method.

Find the rate of the costs. r = rate

18*r = 72

r = 4 cents/inch

Now that you've found the rate you can multiply it by 41 inches to find the cents the wire costs!

41 inch * r (cents/inch) inches cancels out.

41 * 4 = 164

<em>164 cents</em>

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Step-by-step explanation:

2 + (1/10)(1/5)(1/10)2000 = 2 + (1/500)(2000) = 2 + 4 = 6

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3 years ago

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Answer:

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3 years ago

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Answer:

Step-by-step explanation:

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3 years ago

If a rectangle has a length of 5in, a width of 4in, and a height of 8in.Evaluate the volume using the formula: V=LWH 20 inches c

ozzi

Substitute the numbers in the equation:

$V=LWH$

Since L=5in, W=4in and H=8in:

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1 year ago

Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y

I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM = $\mathbf{ = 3 \sqrt{5} }$ i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

$\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }$