Choose the correct function to yield the shown results?
1 answer:
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Answer:
Explanation:
public class Lab8
{
public static double median(double list[])
{
int size=list.length;
if(size%2!=0)
return list[size/2];
else
return(list[size/2-1]+list[size/2])/2.0;
}
public static boolean issorted(double list[])
{
for(int i=0;i<list.length-1;i++)
{
if(list[i]>list[i+1])
return false;
}
return true;
}
public static void findcommon(int a1[],int a2[],int common[])
{
int c=0;
for(int i=0;i<a1.length;i++)
{
boolean isFilled=false;
for(int j=0;j<c;j++)
{
if(a1[i]==common[j])
{
isFilled=true;
break;
}
}
if(isFilled)
{
for(int k=0;k<a2.length;k++)
{
if(a1[i]==a2[i])
{
common[c]=a1[i];
c++;
break;
}
}
}
}
while(c<common.length)
{
common[c]=0;
c++;
}
}
public static void rotateRight(int list[])
{
int temp=list[list.length-1];
for(int i=list.length-1;i>0;i--)
{
list[i]=list[i-1];
}
list[0]=temp;
}
public static int count(int list[],int n)
{
int ncount=0;
for(int i=0;i<list.length;i++)
{
if(list[i]==n)
ncount++;
}
return ncount;
}
public static int[] stretch(int list[])
{
int stretchedList[]=new int[list.length*2];
int k=0;
for(int i=0;i<list.length;i++)
{
int n=list[i];
if(n%2==0)
{
stretchedList[k]=n/2+1;
stretchedList[k+1]=n/2;
}
k+=2;
}
return stretchedList;
}
public static void printDoubleArray(double arr[])
{
System.out.print("[");
for(int i=0;i<arr.length;i++)
{
if(i!=arr.length-1)
System.out.print(arr[i]+",");
else
System.out.print(arr[i]);
}
System.out.println("]");
}
public static void printIntArray(int arr[])
{
System.out.print("[");
for(int i=0;i<arr.length;i++)
{
if(i!=arr.length-1)
System.out.print(arr[i]+",");
else
System.out.print(arr[i]);
}
System.out.println("]");
}
public static void main(String[] args)
{
double list1[]={1.1,2.2,3.3,4.4,5.5,6.6};
double med=median(list1);
System.out.println("List1:");
printDoubleArray(list1);
System.out.println("Median of List1:"+ med);
double list2[]={1.1,2.2,3.3,4.4,6.6,5.5};
boolean result=issorted(list2);
System.out.println("List2:");
printDoubleArray(list2);
System.out.println("List2 is a sorted array.(T/F):"+ result);
int list3[]={3,8,5,6,5,8,9,2};
int list4[]={5,15,4,6,7,3,9,11,9,3,12,13,14,9,5,3,13};
int list5[]=null;
if(list3.length<=list4.length)
list5=new int[list3.length];
else
list5=new int[list4.length];
findcommon(list3,list4,list5);
System.out.println("\n List3:");
printIntArray(list3);
System.out.println("\n List4:");
printIntArray(list4);
System.out.println("\n Array with common value,List5:");
printIntArray(list5);
int list6[]={3,8,19,7};
System.out.println("\n List6:");
printIntArray(list6);
rotateRight(list6);
System.out.println("\n the array after rotate right:");
printIntArray(list6);
int list7[]={3,5,2,1,92,38,3,14,5,73};
int n=count(list7,3);
System.out.println("\n List7:");
printIntArray(list7);
System.out.println("\n the number of occurences of the value 3 in the list 7:"+ n);
int list8[]={18,7,4,24,11};
int list9[]=stretch(list8);
printIntArray(list8);
System.out.println("\n The array after stretching:");
printIntArray(list9);
}
}
Answer:
Following are the code to this question:
l= []#defining an empty list
n=int(input("Enter total element you want to insert: "))#defining variable to input total element
for i in range(0,n):# defining loop to input value in list
insert=int(input())#defining variable insert to input value
l.append(insert) # adding the elemenents into the list
x=n//2#calculating midpoint
l1 =l[:x]#using slicing to hold first-half value in l1 list
l2 =l[x:]#using slicing to hold second-half value in l2 list
print("Before interchange: ")#print message
print ("list : ",l)#print input list
l3=l2 + l1#add value in l3
print("After interchange: ")#print message
#print(l3) #print list l3
print (str(l3)[1:-1])#print list l3
Output:
please find the attachment.
Explanation:
Description of the code:
- In the above python program, an empty list l is declared, in the next line, variable n is defined, that input the total number of the list elements. In the next line, the for loop is declared, which uses the insert variable input value and used the append method to add value in the list.
- In the next step, the variable x is declared, which finds the midpoint of the list, and defines the l1 and l2 lists, that use slicing to hold the first and second half values.
- In the last step, the l3 list is declared, that adds the l1 and l2 lists and use the print method to print its values.
