Answer:
a. 2^6, or 64 opcodes.
b. 2^5, or 32 registers.
c. 2^16, or 0 to 65536.
d. -32768 to 32768.
Explanation:
a. Following that the opcode is 6 bits, it is generally known that the maximum number of opcodes should be 2^6, or 64 opcodes.
b. Now, since the size of the register field is 5 bits, we know that 2^5 registers can be accessed, or 32 registers.
c. Unsigned immediate operand applies to the plus/minus sign of the number. Since unsigned numbers are always positive, the range is from 0 to 2^16, or 0 to 65536.
d. Considering that the signed operands can be negative, they need a 16'th bit for the sign and 15 bits for the number. This means there are 2 * (2^15) numbers, or 2^16. However, the numbers range from -32768 to 32768.
Answer:
A HUB
Explanation:
A hub can described as an hardware or network device use for multi purpose functions like connecting series of internet devices together there by making it possible for all devices to work or function together on a single network.
Hubs are classified into active hub, passive hub, and intelligent hub.
ACTIVE HUB: This type of hub boost the signals but can not perform calculations.
PASSIVE HUB: this type only send the signals but can not boost a signal.
INTELLIGENT HUB: it brings about the boosting of signals and also bring about packets to be analyzed.
Any mobile device contains a(n) accelerometer and gyroscope that can sense even the smallest movements.
<h3>What are accelerometers? What does an accelerometer sensor do in mobile phones?</h3>
The orientation of a mobile phone is determined by the accelerometer in the device. The gyroscope, or gyro for short, tracks rotation or twist to provide another dimension to the data provided by the accelerometer.
A smartphone's built-in accelerometer measures the device's acceleration. It tracks the different motions like shaking, tilting, swinging, and rotating and accordingly changes the orientation of your app. The accelerometer utilizes the value of XYZ to determine and detect motion.
To know more about accelerometer , Visit:
<u>brainly.com/question/27960990</u>
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